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2 years ago

We need to find the percentage of 34 out of 40

Mathematics

1 answer:

FrozenT [24]2 years ago

3 0

Answer:

85%

Step-by-step explanation:

So basically you divide 34 by 40. Which is 85%

If this is your grade, good job!

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2. If y varies inversely as x and<br> y = 3 when x = 5, find x when y = 2.5

4vir4ik [10]

Answer:

Step-by-step explanation:

From the law of variation,

y <> 1/x, where <> is the constant of proportionality. Therefore

y = k/x where k is a constant

3 = k/5 and k = 15

To find x when y = 2.5(5/2)

Go back to the second equation

y = k/x

5/2 = 15/x

When you cross multiply

5x = 30.

Divide through by 5,

x = 6.

8 0

3 years ago

Help please it’s due in 20 minutes

blagie [28]

Answer:

X = 34 (by Pythagoras theorem)

STEP BY STEP:

(30) ^2 +(16)^2 =1156

Root 1156 =34

I hope it helps :))

4 0

2 years ago

Fractions, Decimals<br>Write each as a decimal<br>1) 90%

andrey2020 [161]

Answer:

0.9

Step-by-step explanation:

90%

=90/100

=9/10

=0.9

4 0

3 years ago

Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.

Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0

3 years ago

The following are the annual salaries of 15 chief executive officers of major companies. (The salaries are written in thousands

Alisiya [41]

Answer:

The 25th percentile is 248.

The 70th percentile is 700.

Step-by-step explanation:

The pth percentile is a data value such that at least p% of the data-set is less-than or equal to this data value and at least (100-p)% of the data-set are more-than or equal to this data value.

Arrange the data set in ascending order as follows:

S = {75 , 157 , 224 , 248 , 271 , 381 , 472 , 495 , 586 , 676 , 700 , 723 , 743 , 767 , 1250}

The formula to compute the position of the pth percentile is:

$p^{th} \text{Percentile}=\frac{(n+1)\cdot p}{100}$

Compute the 25th percentile as follows:

$25^{th} \text{Percentile}=\frac{(15+1)\cdot 25}{100}=4^{th}obs.$

The 4th observation from the arranged data set is 248 .

Thus, the 25th percentile is 248.

Compute the 70th percentile as follows:

$70^{th} \text{Percentile}=\frac{(15+1)\cdot 70}{100}\approx 11^{th}obs.$

The 11th observation from the arranged data set is 700.

Thus, the 70th percentile is 700.

4 0

2 years ago