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makvit [3.9K]
3 years ago
10

Find the product. Simplify your answer. (3s+3)(3s–3)

Mathematics
1 answer:
nydimaria [60]3 years ago
7 0

See attachment for math work and answer.

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What are the exact solutions of x2 - 3x - 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x
Vinil7 [7]
x^{2}-3x-5=0 \\  \\ \Delta=(-3)^{2}-4*1*(-5)=9+20=29 \\  \\  \sqrt{\Delta} = \sqrt{29}  \\  \\ x_{1}= \frac{3- \sqrt{29} }{2}  \\  \\ x_{2}= \frac{3+ \sqrt{29} }{2}

<em>\\\ Ben</em>
3 0
3 years ago
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Perform the indicated operation.<br> (4g 2 - 9) ÷ (2g - 3)<br> 2g - 3<br> 2g + 3<br> 2g + 3 R 18
Sveta_85 [38]
(4g^2 - 9) --> this can be factored out.
After factorization, you will get --> (2g-3)(2g+3)

Divide the whole factor by (2g-3)
[ <span>(2g-3)(2g+3) ] / (2g-3)
The final answer is 2g + 3.</span>
5 0
4 years ago
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Simplify, write without exponents.
LuckyWell [14K]

it is helpful to you

4 0
3 years ago
Express the complex number in trigonometric form. -3i
Maksim231197 [3]
Remember to use trig form the general equation is: r(cos(angle) + i sin(angle))
to find r, take √a^2 + b^2 to get 3 for the angle it would be undefined so thee argument would be π / 2. So your answer is 3(cos(π/2) + i sin(π/2))
8 0
3 years ago
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Determine if the given lines are parallel, perpendicular, or neither. A.2-x=3y B.2y+10=6x
kari74 [83]

Answer:

perpendicular

Step-by-step explanation:

2-x =3y

3y = 2-x

y = -1/3x+2/3

slope is -1/3

2y +10 = 6x

2y = 6x -10

y = 3 -5

slope is 3

-1/3 and 3 are negative reciprocals so the lines are perpendicular.

3 0
4 years ago
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