What does 1/4 + 1/3 =

You and a friend are heading to Frankie's Fun Park (Columbia, SC). You have $100 for the day, and plan to spend your time riding

Rufina [12.5K]

Answer:

$8r + 6s = 100$ --- (a)

$s = -2$ ---- (b)

Step-by-step explanation:

Given

Per ride (r) = $8

Per baseballs (s) = $6

Total = $100

Required

Represent using an equation

If 1 ride is $8.

r rides would be 8r

If 1 baseball is $6

s baseballs would be 6r.

So, total is:

$8r + 6s = 100$

Solving (b):

Value of s when r = 14

$8r + 6s = 100$

Substitute 14 for r

$8 * 14 + 6s = 100$

$112+ 6s = 100$

Solve for 6s

$6s = 100 - 112$

$6s = -12$

Solve for s

$s = -12/6$

$s = -2$

4 0

3 years ago

Hi, may someone help me with this?

forsale [732]

I’m not going to tell u the answer but I will try to help you. First off try multiplying then also try to divide. You should get your answer

7 0

2 years ago

Use the given information to write the equation of each ellipse.

Natalija [7]

9514 1404 393

Answer:

x^2/9 +(y +2)^2/49 = 1

Step-by-step explanation:

For center (h, k), and x- and y-semi-axis lengths a and b, respectively, the equation is ...

((x -h)/a)^2 +((y -k)/b)^2 = 1

The given ellipse has center (0, -2) and semi-x-axis length 3 and semi-y-axis length 7. Thus the equation is ...

(x/3)^2 +((y +2)/7)^2 = 1

This might conventionally be written as ...

x^2/9 +(y +2)^2/49 = 1

4 0

3 years ago

One percent of all individuals in a certain population are carriers of a particular disease. A diagnostic test for this disease

Lynna [10]

Answer:

(1) The probability that an individual who tests negative does not carry the disease is 0.9709.

(2) The specificity of the test is 98%.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person carries the disease

<em>Y</em> = the test detected the disease.

Given:

$P(X) = 0.01\\P(Y|X)=0.93\\P(Y|X^{c})=0.02$

The probability of a person not carrying the disease is:

$P(X^{c})=1-P(X)=1-0.01=0.99$

The probability that the test does not detects the disease when the person is carrying it is:

$P(Y^{c}|X)=1-P(Y|X)=1-0.93=0.07$

The probability that the test does detects the disease when the person is not carrying it is:

$P(Y^{c}|X^{c})=1-P(Y|X^{c})=1-0.02=0.98$

(1)

Compute the probability that an individual who tests negative does not carry the disease as follows:

$P(X^{c}|Y^{c})=\frac{P(Y^{c}|X^{c})P(X^{c})}{P(Y^{c}|X^{c})P(X^{c})+P(Y^{c}|X)P(X)} \\=\frac{(0.98\times 0.99)}{(0.98\times 0.99)+(0.07\times 0.01)} \\=0.9709$

Thus, the probability that an individual who tests negative does not carry the disease is 0.9709.

(2)

By specificity it implies that how accurate the test is.

Compute the probability of negative result when the person is not a carrier as follows:

$P(Y^{c}|X^{c})=1-P(Y|X^{c})=1-0.02=0.98$

Thus, the specificity of the test is 98%.

8 0

4 years ago

Graph the radical equation that can be used to calculate the radius, r, of the tank. Use the lowercase "r" and the uppercase "V"

hoa [83]

Tank is made like Cylinder

So let's find r

Radius=r
height=h

$\\ \tt\hookrightarrow V=\pi r^2h$

$\\ \tt\hookrightarrow r^2=\dfrac{v}{h\pi}$

$\\ \tt\hookrightarrow r=\sqrt{\dfrac{v}{3.14h}}$

6 0

3 years ago

Read 2 more answers