Answer:
(1238.845 ;1285.376)
Step-by-step explanation:
Conditions for constructing a confidence interval :
Data must be random
Distribution should be normal and independent ;
Based on the conditions above ; data meets initial conditions ;
C. I = sample mean ± margin of error
Given the data :
1241 1210 1267 1314 1211 1299 1246 1280 1291
Mean, xbar = Σx / n = 11359 / 9 = 1262.11
The standard deviation, s = [√Σ(x - xbar)²/n - 1]
Using a calculator ; s = 37.525
The confidence interval :
C.I = xbar ± [Tcritical * s/√n]
Tcritical(0.10 ; df = n - 1 = 9 - 1 = 8)
Tcritical at 90% = 1.860
C. I = 1262.11 ± [1.860 * 37.525/√9]
C.I = 1262.11 ± 23.266
(1238.845 ;1285.376)
± 23.266
The margin of error :
[Tcritical * s/√n]
[1.860 * 37.525/√9]
C.I = ± 23.266
Answer:
22
Step-by-step explanation:
Answer:
<em>Proved below</em>
Step-by-step explanation:
<u>System of Equations</u>
There are several ways to solve a system of linear equations. One of the most-used is the method of elimination which consists in adding two or more equations to eliminate one or more variables.
The system shown in the question has evidently no solutions because we have the same variables related in the exact same way in the left side of both equations and a different number as a result of those operations.
To prove the statement, let's multiply the first equation by -1

Adding both equations:

This false result comes from the fact that we tried to solve a system with no solutions. The only way we could have solved it is that both right sides had been equal
Answer:
p = -12/11
Step-by-step explanation:
(2-11)p - 2p = 12
-9p - 2p = 12
-11p = 12
p = -12/11