Question

Angles A and B are complementary. Angle B is 8 times as large as

Answer 1

Answer:

Required Answer:-

Let

Angle A=x

Angle B=8x

ATQ

${:}\longrightarrow$$\sf x+8x=90$

${:}\longrightarrow$$\sf 9x=90$

${:}\longrightarrow$$\sf x={\dfrac {90}{9}}$

${:}\longrightarrow$$\sf x=10$

$\therefore$ angle A=10°.