Answer:
1/x-2/3=3/2x
-2/3=3/2x-1/x
-2/3=(3-2)/2x
-2/3=1/2x
by cross multiplication
-2(2x)=1(3)
-4x=3
x= -3/4
Step-by-step explanation:
I hope this will help
plz mark as brainliest
Lets say we have a quadratic equation:
3x^2 + x + 0 = 0
Now, since if we add or subtract 0 from something, the original value stays the same, which means we can write the equation as 3x^2 + x = 0 and ignore the “+0”.
In these kinds of equations, you /can/ use the quadratic formula, but theres a much quicker way. If we factor 3x^2 + x, we get x(3x + 1) = 0. Here, x has two possible values — since the result of the multiplication is 0, that means that either one expression or the other must equal 0. In essence:
If x(3x+1) = 0 then x = 0 or 3x+1 = 0
One of the solutions is that x = 0. Lets find the other.
3x+1=0
3x= -1
x = -1/3
So x1 = 0 and x2 = -1/3. So basically you solve these equations using basic factorization. :)
Answer:
(a) Probability that a triplet is decoded incorrectly by the receiving computer. = 0.010
(b)
(1 – p) = 0.010
(c)
E(x) = 25000 x 0.010
= 259.2
Explanation has given below.
Step-by-step explanation:
Solution:
(a) Probability that a triplet is decoded.
2 out of three
P = 0.94, n = 3
m= no of correct bits
m bit (3, 0.94)
At p(m≤1) = B (1; 3, 0.94)
= 0.010
(b) Using your answer to part (a),
(1 – p) = 0.010
Error for 1 bit transmission error.
(c) How does your answer to part (a) change if each bit is repeated five times (instead of three?
P( m ≤ 2 )
L = Bit (5, 0.94)
= B (2; 5, 0.94)
= 0.002
(d) Imagine a 25 kilobit message (i.e., one requiring 25,000 bits to send). What is the expected number of errors if there is no bit repetition implemented? If each bit is repeated three times?
Given:
h = 25000
Bits are switched during transmission between two computers = 6% = 0.06
m = Bit (25000, 0.06)
E(m) = np
= 25000 x 0.06
= 1500
m = Bit (25000, 0.01)
E(m) = 25000 x 0.010
= 259.2
Answer:
-6x^4-14x^2+12x+2
Step-by-step explanation:
