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3 years ago

An accessories store sells $8 custom socks and $11 custom hats. If 11 items were sold on Monday, and the

Mathematics

1 answer:

Vanyuwa [196]3 years ago

7 0

Answer:

7 socks were sold

Step-by-step explanation:

7*8=56

11-7=4

4×11=44

56+44=100

This proves the answer of 7 to be correct

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A prediction from a line graph is

timurjin [86]

“Line graphs are useful in that they show data variables and trends very clearly and can help to make predictions about the results of data not yet recorded. They can also be used to display several dependent variables against one independent variable.”

“With a line graph, it is fairly easy to make predictions because line graphs show changes over a period of time. You can look at past performance in a line graph and make a prediction about future performance.”

5 0

3 years ago

Read 2 more answers

The perimeter of a triangle is 27. Each side of the triangle has length 2x-3. What is the value of x?

Bezzdna [24]

Answer:

x=6

Step-by-step explanation:

To find the perimeter of the triangle you need to add up all the sides, so if all the sides are 2x-3 the equation will look like this;

2x-3+2x-3+2x-3=27

which when combining like terms will leave it to be;

6x-9=27

Than move all the factors besides x over to the right side;

6x-9+9=27+9

6x = 36

6x/6 = 36/6

x = 6

so your answer will be x=6

8 0

2 years ago

Find the perimeter of rectangle ABCD. That’s the full photo. Only half of the rectangle is provided. You should be able to solve

riadik2000 [5.3K]

Answer:

170°

Step-by-step explanation:

We can already see that measure ∠AD is equal to 85

A square has two halves, so this square will be added.

We will have to add 85 + 85 which equals 170°

5 0

3 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

3 years ago

Substitute 10 for z in z -5 < 7

EleoNora [17]

Then it would be 10-5 < 7
so if you solved it it would be 5 < 7
So this statement is true

4 0

3 years ago