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Yuri [45]
3 years ago
15

1 point Find the length/distance between points (1,3) and (3,15).

Mathematics
1 answer:
pychu [463]3 years ago
6 0

Answer:

12.165525 is the answer

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Don't know how to solve this problem, help would be appreciated
kenny6666 [7]

Answer:

219

Step-by-step explanation:

The figure has the shape of a trapezoid. We find the area of the trapezoid and subtract the area of the rectangular door.

area of trapezoid = (base1 + base2)h/2

area of trapezoid = (20 ft + 12 ft) * 15 ft / 2

area of trapezoid = 32 ft * 15 ft /2

area of trapezoid = 240 ft^2

area of rectangle = length * width

area of rectangle = 7 ft * 3 ft

area of rectangle = 21 ft^2

area to be painted = area of trapezoid - area of rectangle

area to be painted = 240 ft^2 - 21 ft^2

area to be painted = 219 ft^2

Answer: 219 ft^2

6 0
3 years ago
Simplify the expression:<br> -1 + -1 + -3h + -8h
ValentinkaMS [17]

Answer:

-2 + 11h

Step-by-step explanation:

To simplify this equation, you can first combine like terms:

( -1 + -1 ) + ( -3h + -8h )

-2 + -11h

3 0
3 years ago
Using plane K, name a point that is not on the line.
yuradex [85]

Answer:

  H

Step-by-step explanation:

Plane K is shown with two lines. Points on one of them are A, B, G. Points on the other one are G, M, N.

The point in plane K that is not shown on any line is point H.

3 0
1 year ago
7/7q+21= x /5q^2-45 then x=?​
anzhelika [568]

Answer:

x = 5q - 15

Step-by-step explanation:

\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15

3 0
2 years ago
A student is making cookies for a bake sale. He sells 8 snickerdoodles and 12 chocolate chip
lions [1.4K]

Answer:

Snickerdoodles are 0.22$ each and chocolate chip are 0.43$ each

Step-by-step explanation:

using the information in the problem, you can make 2 separate equations: 8x+12y=6.92 and 5x+5y=3.25, let x= the cost of a snickerdoodle and y= the cost of a chocolate chip cookie.

With the 2 equations, we can isolate the y variable of the first equation and simplify which will give us y= -2/3x +6.92/12.

You can now take that equation and plug it into equation number 2:

5x+5(-2/3x + 6.92/12)=3.25.

solve that equation by multiplying 5 through the brackets: 5x-10/3x+34.6/12=3.25

add common terms: 5/3x=4.4/12

find the value of x, you will get x=0.22

plug the value of x (0.22) into one of your equations and solve for the y-value

8 0
3 years ago
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