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4 years ago

Which function forms a geometric sequence when x = 1, 2, 3, ...?

1 answer:

jeka944 years ago

4 0

The geometric sequence is found in the relationship between consecutive terms that is constant.
In this problem, as I understand it, none of the functions forms a geometric sequence.
The functions that form a geometric sequence have the form
f (x) = h (a) ^ n where "a" is the constant relation between the successive terms.
If you wrote the function "f (x) = - 2 (3/4) x", you wanted to write instead:
f (x) = - 2 (3/4) ^ x
So that would be the function that forms a geometric sequence, where the relation between the consecutive terms is 3/4.
You can test it by dividing f (x) / f (x-1)
Then you will see that the result of that division will be 3/4.

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The foodservice department has been asked to prepare a special luncheon for the grandway hospital board of directors on tuesday.

AURORKA [14]

125/21 = 150/x
cross multiply
125x = 3150
x = 3150/125
x = 25.2 lbs....rounded up = 26 lbs <==

5 0

3 years ago

Legalize Marijuana, Part II. As discussed in Exercise 6.12, the 2010 General Social Survey reported a sample where about 48% of

kvv77 [185]

Answer:

Around 2397 Americans must be surveyed to get a margin of error of 2%.

Step-by-step explanation:

We are given the following in the question:

Proportion of US residents who thinks marijuana should be made legal = 48%

$\hat{p} = 0.48$

We have to construct a 95% confidence interval.

Margin of error = 2% = 0.02

Formula for margin of error =

$z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting values, we get,

$0.02 = 1.96\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\0.02 = 1.96\times \sqrt{\dfrac{0.48(1-0.48)}{n}}\\\\\sqrt{n} = 1.96\times \dfrac{\sqrt{0.48(1-0.48)}}{0.02}\\\\\sqrt{n}=48.96\\n = 2397.0816\approx 2397$

Thus, around 2397 Americans must be surveyed to get a margin of error of 2%.

8 0

3 years ago

Mean average of this question plz.

stira [4]

for this answer
I got 32

7 0

3 years ago

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

4 0

4 years ago

Harry drove 2 hours on the freeway then decreased his speed by 20mph and drove 6 more hours. total trip was 352 what was his spe

poizon [28]

Recall your d = rt, distance = rate * time

we know the total trip was 352miles, so, let's say he was going for the first 2hrs at "r" speed, he went "d" miles, then he slowed down to "r - 20" and went 6 more hours, since the total trip is 352 miles, the 6hrs take the slack from 352 - d, and that's how many miles he covered on those 6hours

$\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{before slowing}&d&r&2\\
\textit{after slowing}&352-d&r-20&6
\end{array}
\\\\\\

\begin{cases}
\boxed{d}=2r\\
352-d=(r-20)6\\
----------\\
352-\boxed{2r}=(r-20)6
\end{cases}$

solve for "r".

7 0

4 years ago