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3 years ago

Which function forms a geometric sequence when x = 1, 2, 3, ...?

1 answer:

jeka943 years ago

4 0

The geometric sequence is found in the relationship between consecutive terms that is constant.
In this problem, as I understand it, none of the functions forms a geometric sequence.
The functions that form a geometric sequence have the form
f (x) = h (a) ^ n where "a" is the constant relation between the successive terms.
If you wrote the function "f (x) = - 2 (3/4) x", you wanted to write instead:
f (x) = - 2 (3/4) ^ x
So that would be the function that forms a geometric sequence, where the relation between the consecutive terms is 3/4.
You can test it by dividing f (x) / f (x-1)
Then you will see that the result of that division will be 3/4.

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PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((

krek1111 [17]

Answer:

$\boxed{ - 6} < - \sqrt{24} < \boxed{- 2}$

4 0

3 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago

WILL MARK BRIANLIEST!

gayaneshka [121]

Answer:

(4, - 2 )

Step-by-step explanation:

Given the 2 equations

x + y = 2 → (1)

x - y = 6 → (2)

Adding the 2 equations term by term will eliminate the term in y, that is

(x + x) + (y - y) = (2 + 6)

2x = 8 ( divide both sides by 2 )

x = 4

Substitute x = 4 in either of the 2 equations and solve for y

Substituting in (1)

4 + y = 2 ( subtract 4 from both sides )

y = - 2

Solution is (4, - 2 )

7 0

3 years ago

Plz answer all SHOW WORK

Andrews [41]

Okay, so if it leaks out a pint every hour, and a gallon is 8 pints, it will take 8 hours to leak out 1 gallon. Since there are 24 hours in a day, it would leak out 3 gallons every day. Now, assuming the month we are talking about is 31 days, then we multiply 31 with 3, giving us 93 gallons in a month.
Do you need help with the third too?

8 0

3 years ago

Read 2 more answers

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

tresset_1 [31]

Unable to submit.
Says incorrect answer

4 0

2 years ago