All categories

4 years ago

Need help Urgent !!!! Answer the question on the image.

Mathematics

1 answer:

Nataly_w [17]4 years ago

5 0

144 if a full circle makes 360 and you subtract 72 from it is 288 then you divide it by 2 you get 144. Don’t know if i’m right double check incase!

You might be interested in

How much will a one time investment of $1000 be when invested at 6% for 40 years and compounded annually. Round your answer to t

Vanyuwa [196]

The one time investment of $1000 would worth $10285.72 after 40 years at 6% rate of return

What is annual compounding?

Annual compounding means that the number of times interest is compounded annually is once, compared to semiannual compounding where the interest on the investment is calculated twice a year.

The worth of the investment after 40 years means its future value after having invested $1000 for 40 years using the below formula for future value of a single cash flow:

FV=PV*(1+r)^N

FV=future worth of investment=unknown

PV=initial investment=$1000

r=rate of return=6%

N=number of years of investment=40

FV=$1000*(1+6%)^40

FV=$1000*1.06^40

FV=$1000* 10.2857179371259

FV=$10285.72

Find out more about future value on :brainly.com/question/24703884

#SPJ1

3 0

2 years ago

Read 2 more answers

What is the percent of 60 is 15

frutty [35]

To find the percent of 15 out of 60, you have to divide fifteen by sixty.
Then, you multiply your answer by 100. (We do this because 100 percent is a exact amount. 100% of sixty is...well, sixty.)

15 / 60 = 0.25

Now, we can multiply 0.25 by 100:

0.25 * 100 = 25 (basically just moving the decimal two places to the right.)

Next, add a percent sign:

25%, is your answer.

15 is 25% of 60.

5 0

4 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .