Answer:
B)
Foci: ((sqrt5),0),((-sqrt5),0)
Asymptotes: y=((1/2)x), y=((-1/2)x)
Step-by-step explanation:
Same rule with x before y as I mentioned in the other problem to identify the graph.
Answer:
Already in standard form
Step-by-step explanation:
-4y=10
-4y= by
10= c
And in this case ax=0x, so it will not show up in the equation
0x-4y=10, which is already in standward form
Answer: √(f^2 - 2f + 1) = a
Step-by-step explanation:
We have that:
f^2+g^4-2f+1 = a^2+(g^2)^2
And we want to find the value of a, so we should isolate it.
f^2 + g^4 - 2f + 1 = a^2 + g^(2*2) = a^2 + g^4
where i used that (x^y)^z = x^(y*z)
We can remove the term g^4 in both sides of the equation and get:
f^2 - 2f + 1 = a^2
now we can apply the square rooth to both sides and get
√(f^2 - 2f + 1) = a
So we just found the value of a.
6+6+6+6+6+6+6+6= 48
The perimeter is 48.
