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OLEGan [10]
3 years ago
6

Given h(x) = -5x + 3, find h(5).

Mathematics
1 answer:
cluponka [151]3 years ago
8 0

Answer:

h(5) = -22

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

h(x) = -5x + 3

h(5) is x = 5

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em> [Function]:                                                                                h(5) = -5(5) + 3
  2. Multiply:                                                                                                             h(5) = -25 + 3
  3. Add:                                                                                                                   h(5) = -22
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Solve 9^x + 4 = 11 for x using the change of base formula log base b of y equals log y over log b.
Sauron [17]

Answer:

If you meant 9^x+4=11, then the answer is approximately 0.866.

If you meant 9^{x+4}=11, then the answer is approximately -2.909 which looks like what you meant based on the choices.

Step-by-step explanation:

9^x+4=11

First step is to get the exponential part by itself. The part that has the variable exponent which is the 9^x term.

To do this we need to subtract 4 on both sides:

9^x=11-4

Simplify:

9^x=7

The equivalent logarithmic form is:

\log_9(7)=x

I always say to myself the logarithm is the exponent that is how I know what to put opposite the side containing the log.

Anyways if you don't have options for computing \log_b(a) in your calculator you need to use the change of base formula.

\frac{\log(7)}{\log(9)}=x

So x \approx 0.8856

I don't see this as a choice so maybe you actually meant the following equation:

9^{x+4}=11

Let's see if this is the correct interpretation.

So the exponential part is already isolated.

So we just need to put in the equivalent logarithmic form:

\log_9(11)=x+4

Now we subtract 4 on both sides:

\log_9(11)-4=x

Again if you don't have the option for computing \log_b(a) in your calculator, you will have to use the change of base formula:

\frac{\log(11)}{\log(9)}-4=x

x \approx -2.909

6 0
3 years ago
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snow_lady [41]
HEYA ! ,HERE IS YOUR ANSWER --

We can show or describe the change in position of a figure by graph or chart .


★ hope you like it ★
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A sample of students is taken from the school’s A honor roll. The school estimates that there are actually 360 students on the A
zlopas [31]

Answer:

Number of 8th Graders = 360 - X  

As you can see this question is not complete and lacks the essential data. But we will try to create a mathematical expression to calculate the number of students on the A honor roll which are from 8th grade.

As we know:

Total number of students on the A honor roll = 360

We are asked to calculate, number of students from 8th grade on the A honor  roll.

So, let's assume that "X" represents all the students who are on the A honor roll except 8th grade.

Mathematical Expression:

Number of 8th Graders = Total number of students on the A honor roll - X

Number of 8th Graders = 360 - X

So, if you know the value of X, you can easily calculate the number of students which are from 8th grade on the A honor roll.

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Answer:

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