Question

Find the coordinates of the midpoint of HX

Answer 1

Answer:

$M(29, -12)$

Explanation:

Given:

$H(4\frac{1}{2}, -3\frac{1}{4}), X(2\frac{3}{4}, -2\frac{3}{4})$

Required:

Coordinates of the Midpoint of HX

Solution:

Midpoint (M) of HX, for $H(4\frac{1}{2}, -3\frac{1}{4}), X(2\frac{3}{4}, -2\frac{3}{4})$ is given as

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$.

Let $H(4\frac{1}{2}, -3\frac{1}{4}) = (x_1, y_1)$

$X(2\frac{3}{4}, -2\frac{3}{4}) = (x_2, y_2)$

Thus:

$M(\frac{4\frac{1}{2} + 2\frac{3}{4}}{2}, \frac{-3\frac{1}{4} + (-2\frac{3}{4})}{2})$

Convert to improper fractions

$M(\frac{\frac{9}{2} + \frac{11}{4}}{2}, \frac{-\frac{13}{4} + (-\frac{11}{4})}{2})$

$M(\frac{\frac{18 + 11}{2}}{2}, \frac{\frac{-13 - 11}{4}}{2})$

$M(\frac{\frac{29}{2}}{2}, \frac{\frac{-24}{4}}{2})$

$M(\frac{29}{2}*2, \frac{-24}{4}*2$

$M(29, -12)$