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4 years ago

What are solutions to 40x^22-30x=135

Mathematics

1 answer:

Fiesta28 [93]4 years ago

3 0

Answer:

Step-by-step explanation:

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One card is drawn from a standard deck of cards and then replaced in the deck. Then another card is drawn. What is the probabili

nirvana33 [79]

It’s obviously 15 because if you add all of the sides together you get red and r = 15, so it would be 15/26

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3 years ago

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(x-3)(x+4) please send the help

miss Akunina [59]

Answer:

x^2 + x -12

Step-by-step explanation:

I am going to expand and simplify because you haven't mentioned what to do:

(x-3)(x+4)

x^2 +4x -3x- 12

x^2 +x-12

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3 years ago

Do these side lengths make a triangle? 8 8 4

chubhunter [2.5K]

Answer:

Yes, isosceles triangle

Step-by-step explanation:

Side lengths of 8, 8, and 4 will make an isosceles triangle.

It would look something like this:

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3 years ago

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Select all the options that have the same value as 3 1/2% of 20?

r-ruslan [8.4K]

Solution:

As, we have to find , $3 \frac{1}{2} of 20=\frac{7}{2}$ % of 20

$= \frac{7}{2\times 100}\times 20\\\\ = \frac{7}{10} \\\\ =0.70$

If we have to Percent of a certain number it means , divide that number by 100 , for example x% means $\frac{x}{100}$ .

And if i am writing , x% of y it means , $\frac{xy}{100}$ .

8 0

3 years ago

12 yds

Anton [14]

Answer:

176 square yards

Step-by-step explanation:

The picture of the question in the attached figure N 1

we know that

The area of the walkway around the rectangular pool, is equal to the area of two trapezoids (#1 and #2), plus the area of two smaller rectangles (#3 and #4)

see the attached figure N 2 to better understand the problem

step 1

Find the area of the two trapezoids (#1 and #2)

$A=2[\frac{1}{2}(b_1+b_2)h]$

simplify

$A=(b_1+b_2)h$

we have

$b_1=12\ yd\\b_2=4+12+4=20\ yd\\h=4\ yd$

substitute

$A=(12+20)(4)=128\ yd^2$

step 2

Find the area of the two smaller rectangles (#3 and #4)

$A=2[LW]$

we have

$L=4\ yd\\W=6\ yd$

substitute

$A=2[(4)(6)]=48\ yd^2$

step 3

Find the area of the walkway around the rectangular pool

$128+48=176\ yd^2$

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4 years ago

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