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Dennis_Churaev [7]
3 years ago
7

DRAFT A SPEECH ON THE FOLLOWING TOPICS

Mathematics
1 answer:
olga2289 [7]3 years ago
8 0

Answer:

2. New Years Eve

Step-by-step explanation:

I hope you'll get Best lines for your Speech.

New Year’s Eve is a public holiday in places such as Latvia, the Philippines, and San Marino. It is a holiday for banks in countries such as Bangladesh, Brunei, Paraguay, and Japan (New Year’s Eve is also a government holiday in Japan).

New Year’s Eve is not a nationwide public holiday in countries such as Australia, Canada, the United Kingdom and the United States, but some businesses close early, schools are usually closed, and many people may have half a day off work. Those wishing to travel via public transport may need to check with the local transport authorities on public transport schedules for New Year’s Eve.

Background

New Year's Eve is the last day of the year and the day before New Year’s Day, which marks the start of a new year according to the Gregorian calendar. Pope Gregory XIII introduced the Gregorian calendar in 1582. It was adopted immediately in some areas of Europe but it was not used in various countries until even centuries later. For example, the United Kingdom and the United States started observing the Gregorian calendar in 1752, in which 11 days were dropped.

New Year’s Eve festivities can be traced back to celebrations in Europe that date back before Christianity spread. When many inhabitants in Europe were converted to Christianity, these festivals were merged with Christian beliefs and in time came to mark holidays such as the New Year’s Eve and New Year celebrations.

It is important to note that not all cultures follow the Gregorian calendar in observing New Year’s Eve and New Year’s Day. For example the New Year in the Hindu, Chinese, Coptic, Jewish, Islamic calendars differ to that of the Gregorian calendar.

Symbols

New Year’s Eve and New Year’s Day are symbolized in various ways across the world. Midnight between New Year’s Eve and New Year’s Day is often marked by fireworks and fire crackers. Many people drink and toast with champagne or other sparkling wine.

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Please help, I need this by 10 30 AM
Ainat [17]

Answer:

50 laps

Step-by-step explanation:

20+1.25x+15+2.5x+40+1.5x+25+1.75x=450

7x+100=450

7x+200-200=450-100

7x=350

7x/7=350/7

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5 0
3 years ago
What’s the square root of 9,801?
Butoxors [25]

Answer:

99

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Buy any mistakes in the renaming of the fractions below show the correct remaining 9 / 4 = 9 / 12 2 / 3 + 6 / 12
Klio2033 [76]

Step-by-step explanation:

3/4=9/12 CORRECT

2/3=6/12 FALSE

Step-by-step explanation:

What is done to top of the fraction must be done to the bottom as well in order for the renaming to be true.

3*3 = 9

4*3 = 12

Therefore proven to be true

However,

2*3 = 6

but 3*3 = 9

The second fractions is renamed incorrectly and should be either 2/4=6/12 or 2/3=2/9

Hope this helps!

7 0
3 years ago
Marks $120 bike cost only $80 two years ago. The price of $120 is what percent increase over the previous price of $80?
scoundrel [369]
Use ratio and proportion 80/120=x/100 cross multiply x= 66 2/3 percent
4 0
4 years ago
In a class of students, the following data table summarizes how many students have a cat or a dog. What is the probability that
leonid [27]

Given:

Number of students who has a cat and a dog = 5

Number of students who has a cat but do not have a dog = 11

Number of students who has a dog but do not have a cat = 3

Number of students who neither have a cat nor a dog = 2

To find:

The probability that a student has a cat given that they do not have a dog.

Solution:

Let the following events:

A = Student has a cat

B = Do not have a dog

Total number of outcomes is:

5+3+11+2=21

The probability that a student has a cat but do not have a dog is:

P(A\cap B)=\dfrac{11}{21}

The probability that a student do not have a dog is:

P(B)=\dfrac{11+2}{21}

P(B)=\dfrac{13}{21}

The conditional probability is:

P\left(\dfrac{A}{B}\right)=\dfrac{P(A\cap B)}{P(B)}

P\left(\dfrac{A}{B}\right)=\dfrac{\dfrac{11}{21}}{\dfrac{13}{21}}

P\left(\dfrac{A}{B}\right)=\dfrac{11}{13}

Therefore, the probability that a student has a cat given that they do not have a dog is \dfrac{11}{13}.

5 0
3 years ago
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