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lianna [129]
3 years ago
7

What is the solution -2 = -2​

Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

-2

Step-by-step explanation:

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The ratio of coloured papers to wight papers is 3:8.If there are 48 wight papers, how many coloured papers are there?
mestny [16]

Answer:  The total number of colored papers is 18.

Step-by-step explanation:

Given: The ratio of coloured papers to wight papers is 3:8.

Let total number of colored papers = 3x

and total number of wight papers = 8x

Since, there are 48 wight papers , then

8x=48

\Rightarrow\ x=6

Now , number of colored papers = 3(6)=18

Hence, the total number of colored papers is 18.

4 0
3 years ago
Without measuring angles what is the measure of angle A′ OB ′?
Ede4ka [16]

Answer:

That isn’t possible

Step-by-step explanation:

8 0
3 years ago
PLZZZZZZZZZZZZZZZ HELP I HAVE NO CLUE ON WHAT THE ANSWER ARE!!! PLZZZZZZZZZZZZZZZZZZZZZZZZZ HELP!!!!
koban [17]

Answer:

It would be B & E

Step-by-step explanation:

6 0
3 years ago
Complete the inequality 17/20 ___ 88%
Margarita [4]

Answer:

17/20 < 88%

Step-by-step explanation:

17/20 = .85

.85 < .88

17/20 < 88%


5 0
3 years ago
Read 2 more answers
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
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