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Sedaia [141]
3 years ago
5

Need to know these two problems

Mathematics
2 answers:
Arturiano [62]3 years ago
5 0
Multiple 16 by 1 and then divide by 8 which makes 2.

Multiply 36 by 1 and then divide by 9 which makes 4.
expeople1 [14]3 years ago
5 0
Number 1 is 2 and the answer for 5 is 4
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Kinda forgot how to do this but i got 894.09 for my answer not sure if im right
Andreas93 [3]
You correct the answer is 894.09
7 0
3 years ago
At the airport, the car rental store charges a $25.00 initial rental fee and $30.00 an hour to use the car. What is the total co
Assoli18 [71]
30.00x3=90.00$+25.00$=115.00$ so it has to be 115.00)
5 0
3 years ago
A sample of a radioactive isotope had an initial mass of 360 mg in the year 1998 and
RUDIKE [14]

Answer:

193 mg

Step-by-step explanation:

Exponential decay formula:

  • A_t = A_0e^r^t
  • where Aₜ = mass at time t, A₀ = mass at time 0,  r = decay constant (rate), t = time  

Our known variables are:

  • 1998 to the year 2004 is a total of t = 6 years.
  • The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.

Let's solve for the decay constant of this sample.

  • 270=360e^-^r^(^6^)
  • 270=360e^-^6^r
  • \frac{3}{4} =e^-^6^r
  • \text{ln} (\frac{3}{4} )= \text{ln}(e^-^6^r)
  • \text{ln} (\frac{3}{4} )=-6r
  • r=-\frac{\text{ln}\frac{3}{4} }{6}
  • r=0.04794701

Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.

Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.

  • A_t=270e^-^(^0^.^0^4^7^9^4^8^0^1^)^(^7^)
  • A_t=270e^-^0^.^3^3^5^6^2^9^0^7
  • A_t=193.01982213

The expected mass of the sample in the year 2011 would be 193 mg.

3 0
3 years ago
Please help ASAP!!!!!!
erica [24]

Answer:

300

Step-by-step explanation:

20*30=600

600/2=300

Please mark as Brainliest! :)

Have a nice day.

6 0
4 years ago
An online DVD rental site charges a monthly membership fee of $10,
Taya2010 [7]

Answer:

666

Step-by-step explanation:

5 0
3 years ago
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