Hey!
Hope this helps...
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So to solve this, we want to know how many miles can we do in every 1 gallon of gas.
To solve this, we do: 380 / 14 = 27.14 miles for every 1 gallon
Okay, so if we have 1/2 a gallon stashed away, how far can we get on every 1/2 gallon...
To solve this, we do: 27.14 / 2 = 13.57 miles for every 1/2 gallon
So...
The answer is: We will NOT be able to get to the Gas Station that is 15miles away, because we can only go about 13.5 miles with every 1/2 gallon.
Answer:
x=2
Step-by-step explanation:
4x+6=x+12
-x -x
3x+6=12
-6 -6
3x=6
/3 /3
x=2
Given:
Nana has a water purifier that filters
of the contaminants each hour.
Water has contaminants = ![\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D)
To find:
The function that gives the remaining amount of contaminants in kilograms, C(t), t hours after Nana started purifying the water.
Solution:
Let C(t) be the remaining amount of contaminants in kilograms after t hours.
Initial amount of contaminants = ![\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D)
Decreasing rate is
.
Using the exponential decay model:
![C(t)=C_0(1-r)^t](https://tex.z-dn.net/?f=C%28t%29%3DC_0%281-r%29%5Et)
where,
is initial amount of contaminants, r is the decreasing rate and t is time in hours.
Substituting the values, we get
![C(t)=\dfrac{1}{2}(1-\dfrac{1}{3})^t](https://tex.z-dn.net/?f=C%28t%29%3D%5Cdfrac%7B1%7D%7B2%7D%281-%5Cdfrac%7B1%7D%7B3%7D%29%5Et)
![C(t)=\dfrac{1}{2}(\dfrac{2}{3})^t](https://tex.z-dn.net/?f=C%28t%29%3D%5Cdfrac%7B1%7D%7B2%7D%28%5Cdfrac%7B2%7D%7B3%7D%29%5Et)
Therefore, the required function is
.