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3 years ago

Please help please help please help please help please help please help please help please help

Mathematics

1 answer:

Irina-Kira [14]3 years ago

4 0

Answer:

its third one

Step-by-step explanation:

y= -2

-2=[3x(-5/3)+5]-2

0= -5+5

0=0

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What is the square root of 49<br> giving brainliest

tia_tia [17]

Answer:

Step-by-step explanation:

here 7×7 = 49

So the square root of 49 is 7.

Hope it helps you!!

#IndianMurgaツ

4 0

2 years ago

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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

3 years ago

Two random samples of 40 students were drawn independently from two populations of students. Assume their aptitude tests are nor

dybincka [34]

Answer:

b. Do not reject the null hypothesis

Step-by-step explanation:

Given that two random samples of 40 students were drawn independently from two populations of students. Assuming equal variances

we have the following data.

Sample 1

Mean:

Standard deviation:

Sample size:

Sample 2

Mean:

Standard deviation:

Sample size:

$H_0: \bar x_1=\bar x_2\\H_a: \bar x_1\neq \bar x_2$

Difference -3.000

Standard error 1.681

95% CI -6.3462 to 0.3462

t-statistic -1.785

DF 78

Significance level P = 0.0782

Since p value >0.05,

b. Do not reject the null hypothesis

7 0

4 years ago

I am a product. one of my factors is 7. the sum of my factors equals 11. what number am i

sveta [45]

The number you’re looking for is 4 Hope I helped

6 0

3 years ago

Solve for g:

yulyashka [42]

$\dfrac{5}{8}=\dfrac{12}{g}\ \ \ |\text{cross multiply}\\\\5\cdot g=8\cdot12\\\\5g=96\ \ \ |:5\\\\g=19.2$

5 0

3 years ago

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