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Elza [17]
3 years ago
8

A bag of rice weighs 20 kg more than one of sugar. If 50 kg of sugar is added to the second bag, its weight becomes twice that o

f the bag of rice. Find the weight of the bag of rice ​
Mathematics
2 answers:
andriy [413]3 years ago
3 0
The bag of rice is 30 kg and the bag of sugar is 10kg
30kg is 20kg more than 10kg
Then 10kg+50kg = 60kg
Which is twice the 30kg bad of rice
lord [1]3 years ago
3 0

Answer:

Rice= 25kg

Step-by-step explanation:

Okay so... The rice is 20 more than the sugar...

Let's visualize it as r20>s'x'

Sugar then becomes s50x>r20

Because the sugar has now been added 50kg it is twice as much as the rice, so whats half of 50? 25! That's the weight of the rice!

The sugar weighs 5kg, since at the beginning it said the rice weighed 20kg more.

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4 0
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The edges of a cube increase at a rate of 2 cm divided by s. How fast is the volume changing when the length of each edge is 40
Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

Let the edge of the cube be a .

Given

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\frac{dV}{dt} = 3a^ 2\frac{da}{dt}

= 3a² x 2

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If a = 40 cm

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5 0
3 years ago
Which equation could be solved using this application of the quadratic formula?
Alex_Xolod [135]

Answer:

C. x^2 + 2x - 1 = 3

Step-by-step explanation:

The standard form of a quadratic equation is

ax^2 + bx + c = 0

We need to use the quadratic formula and the given expression to find the values of a, b, and c.

The quadratic formula is

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Where the formula has -b, the problem has -2, so b = 2.

Now we have

ax^2 + 2x + c = 0

In the denominator, where the formula has 2a, the problem has 2(1), so a = 1.

Now we have

x^2 + 2x + c = 0

Inside the root, the quadratic formula has -4ac. the problem shows -4(1)(-4). Since we already know that a = 1, then c = -4.

Now we have

x^2 + 2x - 4 = 0

Let's look at choice A.

x^2 + 1 = 2x - 3

Subtract 2x from both sides. Add 3 to both sides.

x^2 - 2x + 4 = 0   <em>This is not it!</em>

Let's look at choice B.

x^2 - 2x - 1 = 3

Subtract 3 from both sides.

x^2 - 2x - 4 = 0     <em>This is not it!</em>

Let's look at choice C.

x^2 + 2x - 1 = 3

Subtract 3 from both sides.

x^2 + 2x - 4 = 0     <em>This is it!</em>

Answer: C. x^2 + 2x - 1 = 3

8 0
3 years ago
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SpyIntel [72]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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