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3 years ago

Find the mean of the following set numbers 10,15,25,30,30,50,55,55,60,80

Mathematics

2 answers:

den301095 [7]3 years ago

5 0

Answer:

the pattern is add 5 then addd 10

Step-by-step explanation:

look at what you typed

dalvyx [7]3 years ago

3 0

Answer:

The answer is 41.

Step-by-step explanation:

To find the mean you have to add up all the numbers and then divide it by how many numbers there are.

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Ilia_Sergeevich [38]

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6 0

3 years ago

URGENT!!!!!!!! PLEASE HELP ASAP TIMED!!!!!!!!!!!!!!! HELP!!!!!!!!!!!!!!!!!

rodikova [14]

Answer:

x = 18 and y = 6√10

Step-by-step explanation:

First using pythagoras theorem on the small triangle

h² = 6² + 2²

h² = 36 + 4

h² = 40

h= √40

h = √4 * 10

h = 2√10

Using the similarity theorem;

y/2√10 = 6/2

y/√10 = 6

y = 6√10

To get x we will use the pythagoras theorem

y² = x²+6²

(6√10)² = x² + 36

360 = x² + 36

x² = 360 - 36

x² = 324

x = 18

Hence x = 18 and y = 6√10

5 0

3 years ago

Solve the formula <br> F=ma for a<br> plss

barxatty [35]

Answer:

Step-by-step explanation:

F = ma

ma = F

a = F/m

8 0

3 years ago

Write the value of 83,479

Ann [662]

Eighty three thousand four hundred and seventy nine

6 0

3 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

3 years ago