Differentiate both sides with respect to
:
When
, you have
For part (b), we now assume that
and
are functions of an independent variable, which we'll call
(for time). Now differentiating both sides with respect to
, we have
where the chain rule is used on the right side. We're told that
is decreasing at a constant rate of 0.1 units/second, which translates to
. So when
, you have
where the unit is again units/second.
898316287940
hope this helps, back to my hole i go
You calculate the markup or markdown in absolute terms (you find by how much the quantity changed), and then you calculate the percent change relative to the original value. So they're really just another form of "increase - decrease" exercises.
Example:
A computer software retailer used a markup rate of 40%. Find the selling price of a computer game that cost the retailer $25.
The markup is 40% of the $25 cost, so the markup is:
(0.40)(25) = 10
Then the selling price, being the cost plus markup, is:
25 + 10 = 35
The item sold for $35.
Answer: The 7th term is 8192
Answer:
The correct answer would be B
Step-by-step explanation:
(x,y)
y-x>-3
6-2>-3
4>-3
