Answer:
13 and 14.
Step-by-step explanation:
So we have two consecutive integers.
Let's call the first integer a.
Since the integers are consecutive, the other integer must be (a+1) (one more than the last one).
We know that the sum of the greatest integer (or a+1) and twice the lesser integer (a) is 40. Therefore, we can write the following equation:

The first term represents the greatest integer. The second term represents 2 times the lesser integer. And together, they equal 40.
Solve for a. Combine like terms:

Subtract 1 from both sides. The 1s on the left cancel:

Divide both sides by 3:

Therefore, a or the first integer is 13.
And the second integer is 14.
And we can check:
14+2(13)=14+26=40
Answer:
okok so the anwser is 1+1
Step-by-step explanation:
1 and add another is 2
boom.
:)
Answer:
-3 is the answer
Step-by-step explanation:
distribute the value of n
3+4-5×2
=7-10
=-3
Take second equation here,
2x + 9 = -12
2x = -12 - 9
2x = -21
Multiply by 2,
4x = -42
Now, substitute the vaue of 4x in 1st equation,
-42 - y = 2
-y = 2 + 42
y = -44
In short, Your Answer would be -44
Hope this helps!
Hope this helps.................