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jok3333 [9.3K]
2 years ago
12

PLEASE HELP I NEED THIS ASAP (I hate math)

Mathematics
1 answer:
Arlecino [84]2 years ago
8 0

Answer: A) x - 4 = 0 and this is an undefined slope which is a vertical line

Step-by-step explanation:

If the slope of a line is undefined, then the line is a vertical line, so it cannot be written in slope-intercept form, but it can be written in the form: x=a , where a is a constant.

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Solve the equation. 2(3x – 5) = 8
stiks02 [169]

You would distibute first distribute

6x-10=8

add 10 on both sides

6x=18

Then you divide 6 on both sides to get x by itself so

x=3

4 0
3 years ago
What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1? A. Dis
Firlakuza [10]

Answer:

The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)  

Step-by-step explanation:

\text{The function is given to be : }f(x)=\frac{3x^2+x-4}{x-1}\\\\\implies f(x)=\frac{(3x+4)(x-1)}{(x-1)}

To find the point of discontinuity :

Put the denominator equal to 0

⇒ x - 1 = 0

⇒ x = 1

Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1

⇒ y = 7

So, Point of discontinuity : (1, 7)

And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0

⇒ 3x + 4 = 0

⇒ 3x = -4

⇒ x = negative four thirds ( zero of the function)

Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

4 0
3 years ago
Read 2 more answers
Write the improper fraction as a mixed number in simplest form. 11/2
pantera1 [17]

Answer:

5 and 1/2

Step-by-step explanation: 2 goes into 11 5 times without passing it. That one that is left over would be the numerator and 2 as the demonator.

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3 years ago
Write as an expression:<br> the total of n and 16
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Total is just add
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THE FUNCTION ARCSINE CAN ALSO BE DEFINED AS?
vodomira [7]
The arcsine, \sin^{-1}, is the inverse of the \sin function. This means that it takes as <em>inputs </em>what would usually be <em>outputs </em>for the \sin function and produces as <em>outputs </em>what would usually be <em>inputs </em>for the \sin function.

This can be particularly useful when you're trying to find an angle on a right triangle, but you've only been given the lengths of the sides. To find any angle \theta in a right triangle, just take \sin^{-1} \frac{o}{h}, where o is the side opposite \theta and h is the hypotenuse of the right triangle.

3 0
3 years ago
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