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3 years ago

5

help please. Plot two points, C and D, which stay in the same place when they are reflected over line f. Plot two other points,

E and F, which move when reflected over line f.

1 answer:

mart [117]3 years ago

8 0

Answer:

just invert the points

Step-by-step explanation:

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Please answer correctly

TiliK225 [7]

Answer:

Step-by-step explanation:

Since side BC = side AD (because opposite side of a parallelogram are congruent)

Angle C = angle A(because opposite angles of a parallelogram are congruent)

side DC = side AB(because the opposite sides of a parallelogram are congruent. Therefore,

Triangle ABD is congruent to triangle CDB by the postulate of SAS which means side angle side.

3 0

3 years ago

How do you write 20 in exponential form

seropon [69]

Answer:

2 to the power of 2 times 5 to the power of 1

= 20

Step-by-step explanation:

6 0

3 years ago

Find the modulus of the complex number 6-2i

Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

Step-by-step explanation:

Given the number

$6-2i$

We know that

$z = x + iy$

where x and y are real and $\sqrt{-1}=i$

The modulus or absolute value of z is:

$|z|\:=\sqrt{x^2+y^2}$

Therefore, the modulus of $6-2i$ will be:

$z=6-2i$

$z=6+(-2)i$

$|z|\:=\sqrt{x^2+y^2}$

$|z|\:=\sqrt{6^2+\left(-2\right)^2}$

$=\sqrt{6^2+2^2}$

$=\sqrt{36+4}$

$=\sqrt{40}$

$=\sqrt{2^2}\sqrt{2\cdot \:5}$

$=2\sqrt{2\cdot \:5}$

$=2\sqrt{10}$

Therefore, the modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

3 0

3 years ago

Grayson's cell phone plan charges a flat fee of $40 for data and calls and an additional $0.10 per text message sent or received

ANTONII [103]

Answer:

0.67 cents

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20%20%5Cfrac%7Bw%7D%7B3%7D%20" id="TexFormula1" ti

ElenaW [278]

Answer: $\bold{w=\dfrac{6y-3}{2}}$

<u>Step-by-step explanation:</u>

Isolate w by performing the following steps

Multiply by 6 on both sides to clear the denominator
Subtract 3 from both sides
Divide both sides by 2

$y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}$

5 0

3 years ago