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Dimas [21]
3 years ago
5

help please. Plot two points, C and D, which stay in the same place when they are reflected over line f. Plot two other points,

E and F, which move when reflected over line f.

Mathematics
1 answer:
mart [117]3 years ago
8 0

Answer:

just invert the points

Step-by-step explanation:

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Please answer correctly
TiliK225 [7]

Answer:

Step-by-step explanation:

Since side BC = side AD (because opposite side of a parallelogram are congruent)

Angle C = angle A(because opposite angles of a parallelogram are congruent)

side DC = side AB(because the opposite sides of a parallelogram are congruent. Therefore,

Triangle ABD is congruent to triangle CDB by the postulate of SAS which means side angle side.

3 0
3 years ago
How do you write 20 in exponential form
seropon [69]

Answer:

2 to the power of 2 times 5 to the power of 1

= 20

Step-by-step explanation:

6 0
3 years ago
Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
3 years ago
Grayson's cell phone plan charges a flat fee of $40 for data and calls and an additional $0.10 per text message sent or received
ANTONII [103]

Answer:

0.67  cents

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20%20%5Cfrac%7Bw%7D%7B3%7D%20" id="TexFormula1" ti
ElenaW [278]

Answer:  \bold{w=\dfrac{6y-3}{2}}

<u>Step-by-step explanation:</u>

Isolate w by performing the following steps

  • Multiply by 6 on both sides to clear the denominator
  • Subtract 3 from both sides
  • Divide both sides by 2

y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}

5 0
3 years ago
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