Answer:
(f+g)(2) = 4
(f-g)(4) = 8
(f ÷g)(2) = 7
(f x g)(1) = 0
Step-by-step explanation:
We are given these following functions:


(f+g)(2)

At 

Then
(f+g)(2) = 4
(f-g)(4)

At x = 4

Then
(f-g)(4) = 8
(f ÷g)(2)

At x = 2

Then
(f ÷g)(2) = 7
(f x g)(1)

Then

So
(f x g)(1) = 0
Answer:
x+4y=-35
-8x-4y=28
Step-by-step explanation:
The answer to the original equations is (1, -9). You can solve that by using substitution by moving the 4y over and substituting that equation for x on the second part of the top equation. Using elimination, the second set of answers will give you the same, (1, -9)!
Tank calculations :
Volume = 1/4(4/3 * pi * r^3)
r= 70 feet.
Volume = 1/4(4/3 * 3.14 * 70^3)
Calculating the values:
Volume = 359,000.67 ft.cubed
No we divide the actual radius by 6 to get the volume of scale model.
Hence,
6^3 = 216 times smaller.
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X² - 14x + 33 = 0 is in the form ax² + bx + c = 0. We will need this for the second step.
Subtract 33 from both sides
x² - 14x = - 33
Divide the b term by 2 and then square the result. Then add that to both sides.
- 14 / 2 is - 7. (- 7)² = 49. Add that to both sides
x² - 14x + 49 = - 33 + 49
Combine the constants and factor the trinomial
(x - 7)² = 16
Square root both sides
x - 7 = +/- 4
or
x - 7 = - 4 and x - 7 = 4
You have to place a plus-minus statement because (- 4)² and 4² both equal 16.
Now we solve for x in each equation. Add 7 to both sides to isolate our variable.
x = 3 and x = 11