The total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Since an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached. The heights of the trapezoids and the apothem of the hexagon measure 2 centimeters each, and the length of the shorter base of each trapezoid is 1.5 centimeters, the radii of the hexagon, and the base of the trapezoid form a triangle of
- height, h = apothem of the hexagon = 2 cm and
- base, b = length of shorter base of trapezoid.
<h3>Area of the triangle</h3>
So, the area of this triangle is A = 1/2bh
= 1/2 × 1. 5 cm × 2 cm
= 1.5 cm × 1 cm
= 1.5 cm²
<h3>Area of the hexagon</h3>
Since there are 6 of such triangles in the hexagon, the area of the hexagon, A' = 6A
= 6 × 1.5 cm²
= 9.0 cm²
So, the total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²
Learn more about area of a hexagon here:
brainly.com/question/369332
Begin
3x-4=14
3x=18
x=6
.5n=1.25
n=2.5
x+1=2x-2
x+3=2x
3=x
x+3=10
x=7
6x-13=-11
6x=2
x=1/3
p=4-p
2p=4
p=2
End
1/2bh
1/2b4 = 18
b4= 36
b= 9 yards
La respuesta es 6.92 en su expresión más pequeña porque dice la altura de un triángulo equilátero es igual solo sacas las fórmula de la altura de un triángulo que es a^2=c^2+B^2 osea haci que sustituye con valores h^2= 8^2-4^2=h^2 8x8=64 4x4=16 64-16= √48 = 6.92
