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Alina [70]
3 years ago
15

A random sample has been taken from a population. A statistician, using this sample, needs to decide whether to construct a 90 p

ercent confidence interval for the population mean or a 95 percent confidence interval for the population mean. How will these intervals differ?
Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

Step-by-step explanation: a confidence interval is a range that shows how precise the measurement is. if a statistician decides to construct using 90 percent C I over a 95% C I, it tells you that you have 10% chance of being wrong rather than 5% chance of being wrong while using the 95%. Also a 90 percent confidence interval would be narrower than a 95 percent confidence interval

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Let 2n+1 be the smaller integer. The larger integer is then 2n+3, and we have

(2n+1)^2=10+(2n+3)\implies4n^2+4n+1=2n+13

\implies4n^2+2n-12=0

\implies2n^2+n-6=0

\implies(2n-3)(n+2)=0

\implies 2n-3=0\text{ or }n+2=0

\implies n=\dfrac32\text{ or }n=-2

We omit n=-2, since 2(-2)+1=-3 is negative.

Then for n=\dfrac32 we find 2\left(\dfrac32\right)+1=4, but this is not odd.

There are no consecutive odd integers that satisfy the given condition!

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