Answer:
put only 2 in the denominator and change the exponent to a positive with it
Step-by-step explanation:
Answer:
- ∠CDE ↔ 50°
- ∠FEG ↔ 75°
- ∠ACB ↔ 55°
Step-by-step explanation:
To solve angle problems like this, you make use of three relations:
- linear angles have a sum of 180°
- angles in a triangle have a sum of 180°
- vertical angles have the same measure
The attached diagram shows the measures of all of the angles of interest in the figure. The ones shown in blue are the ones that have the measures and names on the list of answer choices.
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A good place to start is with the linear angle pair at A. Since the sum of the two angles is 180°, the angle at A that is inside the triangle will be ...
180° -130° = 50°
Then the missing angle in that triangle at C will have the measure that makes the sum of triangle angles be 180°:
∠ACB = 180° -50° -75° = 55° . . . . . this is one of the angles on your list
Similarly, the angle at E inside triangle FEG will have a measure that makes those angles have a sum of 180°:
∠FEG = 180° -60° -45° = 75° . . . . . this is one of the angles on your list
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The two angles whose measures we just found are vertical angles with the base angles in triangle CDE, so that triangle's angle D will have a measure that makes the total be 180°.
∠CDE = 180° -55° -75° = 50° . . . . . this is one of the angles on your list
Answer:
The correct answer is B :)
Step-by-step explanation:
The number of k-combinations(5) from a given set S of n (24) elements
Calculating the number of combinations
Substituting our values for n= 24 and k= 5 we get
24C5 = 24!5!(24−5)!
Subtracting 5 from 24 is 19
24!5!(19)!
Expending factorial
24X23X22X21X20X19!(5X4X3X2X1)X19!
Cancelling common factors
24X23X22X21X205X4X3X2X1
Multiply numerator values and denominator values
5100480120
Divide the 5100480 by 120
Final Result :42504.0
There are 42504.0 combinations to choose 5 items out of a set of 24
The seventh grade completed more assignments than sixth and eighth grade did.
The notation
h: x --> ax+b
is another way of saying h(x) = ax+b
The input is x, the output is h(x) = ax+b
The composite function notation h^2 is the same as (h o h)(x) or h(h(x)). I prefer h(h(x)) as it is the most descriptive of the three notation styles. The square notation is easily confused with actual squaring (when instead we want composite notation of a function with itself)
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h(x) = ax+b
h(x) = a( x )+b
h(h(x)) = a( h(x) )+b ... replace every x with h(x)
h(h(x)) = a( ax+b )+b .... replace the h(x) on the RHS with ax+b
h(h(x)) = a*ax + ab + b
h(h(x)) = a^2*x + (ab + b)
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Since h(h(x)) = 36x-35, this means we can equate the two expressions to find a and b
a^2*x + (ab+b) = 36x-35
we see that
a^2 = 36, so a = 6 (keep in mind a > 0)
since a = 6, we know that
ab+b = -35
6b+b = -35
7b = -35
b = -35/7
b = -5