Answer:
(a) 0.0128 to 4 decimal places
(b) The 90% confidence interval is 119.1 < μ < 121.0 to 1 decimal places
Step-by-step explanation:
See the attached documents and graphs. Cheers!
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pdf
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Answer:
Question 1: 11%
Question 2: 89%
Question 3: 43%
Question 4: 11%
Step-by-step explanation:
Looking at picture 1, we need to find the crossing point between -1.2 and 0.05. That has 0.1056, which is the same as 10.56%. 10.56% rounds to 11%, so C is our answer.
Picture 2 has the same chart, but we just need to find the inverse, since the inequality sign is flipped. 100 - 10.56 is 89.44%, which rounds to 89%, so D is the answer for Picture 2.
Picture 3 has two tables. 0.73 has 76.73% and -0.41 has 34.09%. Subtract 34.09% from 76.73% to get 42.64% That rounds to 43%, so A is the answer.
Picture 4 essentially has the same expression as Picture 2 (only the sign has switched): P(z ≥ 1.25). The meeting point is 89.44%. Now, subtract that from 100 to get 10.56%, which rounds to 11%. C is our answer for Picture 4.
I hope this helps you! ^w^
S I can
which linear equation due u want?
Answer:
x = -1
x = 5
Step-by-step explanation:
Use pythagorean theorem: a² + b² = c²
x² + (2x + 2)² = (2x + 3)²
Since these are quantities, you'll have to make them into quadratic equations.
(2x + 2)(2x + 2) = 4x² + 4x + 4x + 4
(2x + 3)(2x + 3) = 4x² + 6x + 6x + 9
x² + 4x² + 4x + 4x + 4 = 4x² + 6x + 6x + 9
Combine like terms
5x² + 8x + 4 = 4x² + 12x + 9
Move one side to set the equation equal to 0
x² - 4x - 5 = 0
Solve
x² - 5x + x - 5 = 0
x(x - 5) + 1(x - 5) = 0
(x + 1)(x - 5) = 0
x = -1, 5
<em>We</em><em> </em><em>can</em><em> </em><em>check</em><em> </em><em>that</em><em> </em><em>these</em><em> </em><em>are</em><em> </em><em>correct</em><em> </em><em>by</em><em> </em><em>plugging</em><em> </em><em>them</em><em> </em><em>in</em><em> </em><em>for</em><em> </em><em>x</em><em> </em><em>and</em><em> </em><em>seeing</em><em> </em><em>if</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>equal</em>
<em>For</em><em> </em><em>example</em>
<em>(</em><em>-1</em><em>)</em><em>²</em><em> </em><em>+</em><em> </em><em>(</em><em>2</em><em>(</em><em>-1</em><em>)</em><em> </em><em>+</em><em> </em><em>2</em><em>)</em><em>²</em><em> </em><em>=</em><em> </em><em>(</em><em>2</em><em>(</em><em>-1</em><em>)</em><em> </em><em>+</em><em> </em><em>3</em><em>)</em><em>²</em>
<em>1</em><em> </em><em>=</em><em> </em><em>1</em>
