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murzikaleks [220]
2 years ago
11

Warm-Up: Solve each equation for x. 1. x + 5 = 15

Mathematics
2 answers:
GarryVolchara [31]2 years ago
6 0

Answer:

x = 10

Step-by-step explanation:

x + 5 = 15

x = 15 - 5

x = 10

Thus, x = 10

<u>-TheUnknown</u><u>Scientist</u>

eduard2 years ago
5 0
X+5=15
-5 -5
X=10
Hope this helps!!
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Using the traditional formula, a 95% CI for p1 − p2 is to be constructed based on equal sample sizes from the two populations. F
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Answer:

49

Step-by-step explanation:

Given:

Width = 0.4

Let's take the z value of 95% which is = 1.96

Let's assume population proportion p1 and p2 = 0.5

For margin of error E, the relation between the width and margin of error is 2E.

i.e 2E = 0.4

E = 0.2

To find the sample size, n, let's use the formula :

n= \frac{z^2*(p_1(1-p_1) + p_2(1-p_2))}{E^2}

= \frac{1.96^2(0.5(1-0.5)+0.5(1-0.5))}{0.2^2}

= 48.02

≈ 49

8 0
3 years ago
You are building a flower bed with a perimeter of 16 feet. The length of the bed is 4 feet longer than the width. What are the d
kykrilka [37]

Answer:

Step-by-step explanation:

The perimeter is basically the outline of the shape. The perimeter of a rectangle is given by P=2l+2w, where l is the length and w is the width. Thus, the perimeter of the flower bed would be given by P=2(3n5o)+2(5n5o).

6 0
2 years ago
Suppose you hear a weather forecaster say a front is forming over your area. However, you don’t hear what kind of front it is. W
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Answer:

The conclusion that you can raw about the coming weather is : you could assume the weather will be stormy and unsettled, since all kind of fronts uusally bring some form of precipitation.

Step-by-step explanation:

8 0
3 years ago
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Multiply the following fractions. 5/8 X 7/10 =
lubasha [3.4K]
The answer is 7/16 .
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3 years ago
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Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?
Mademuasel [1]

Answer:- a.The given expression is equivalent to  \frac{x^{10}y^{14}}{729}



Given expression:- [\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}

=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}

=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}

=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}

=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}

=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}

Thus a. is the right answer.


6 0
3 years ago
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