Answer:
<h2>
√34sin(x + 0.33π)</h2>
Step-by-step explanation:
The general form of the equation acosx + bsinx = Rsin(x + e) where R is the resultant of the constants 'a' and 'b' and e is the angle between them.
R = √a²+b²

Given the function f(x) = 3 cos x + 5 sin x, comparing with the general equation;
a = 3, b = 5
R = √3²+5²
R = √9+25
R =√34

in radians;
 
3 cos x + 5 sin x = √34sin(x + 0.33π)
 
        
             
        
        
        
Answer:
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
   15°
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°.  Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.
 
        
             
        
        
        
Answer:
23+19+27+x = 96
x > 27
not sure if the answer can be left that way or do you assume that test results are whole numbers, if so then the answer  would b=have to be 28.. but I think that >27 is the answer expected
Step-by-step explanation: