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Nana76 [90]
3 years ago
13

Could anyone give a hand?

Mathematics
1 answer:
Lana71 [14]3 years ago
6 0

Answer: 73.5

first you work out the total area of this shape.

area: 105

this mean you can start working out the non-shaded area to do this you need to multiply 7cm with 6cm which is 42cm then you divide by 2 to get 21cm.

then to work ou the other non-shaded area in the left you multiply 3cm and 7cm together getting 21cm you then divide it and you get 10.5.

you then add 10.5cm and 21cm together to get 31.5cm, subtract that answer with the total area which gets the answer 73.5!

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5(x+2)=6x+3x-14 please solve
zavuch27 [327]

Answer:

5(x+2)=6x+3x−14

Step 1: Simplify both sides of the equation.

5(x+2)=6x+3x−14

(5)(x)+(5)(2)=6x+3x+−14(Distribute)

5x+10=6x+3x+−14

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5x+10=9x−14

Step 2: Subtract 9x from both sides.

5x+10−9x=9x−14−9x

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Step 3: Subtract 10 from both sides.

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Step 4: Divide both sides by -4.

−4x

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3 years ago
I dont know how to solve this one ​
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Read 2 more answers
The measurement of the edge of a cube is measured to be 12 inches, with a possible error of 0.03 inch. Use differentials to appr
adoni [48]

Answer:

A) possible error = 12.992

Possible values for the volume [1715,007,1740.992]

B) possible error = 4.325

Possible values for the surface area [859,675,868,325]

Step-by-step explanation:

The volumen of a cube is the cube of the length of a side. Thus, the meassurement of the volume is 12³ = 1728 inches³. To calculate the error, lets call Y the real value of the length,

Y = X + e, where e is the error and X = 12.

Y³ = (X+e)³ = X³ + 3X²e + 3Xe² + e³

the error is 0.03 inches, so we have that

Y³ = X³ + 12.96+0.0324+ 0.000027 = X³+12.992427 = X³+12.992 (rounded to 3 decimal places).

Thus, the absolute possible error is Y³- X³ = 12.992, and the volume of the cube is contained in the interval [X³-12.992,X³+12.992] = [1715,007,1740.992]

B) The surface area is 6 X². With X meassured as 12, the surface area is meassured by 6*12² = 864.

To calculate the absolute error, we take Y = X+e, with X and e as before. We have

6 Y² = 6*(X+e)² = 6X²+12Xe+6e² = 6X²+4.32+0.0054 = 6X²+4.3254

Hence, the absolute error is bounded by 6Y²-6X² = 4.3254 rounded by 4.325, and the value of the surface area is contained in the interval [6X² -4.325, 6X²+4.325] = [859,675, 868,325]

3 0
3 years ago
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