<span>H(t) = −16t^2 + vt + s
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<span>H(t) = −16t^2 + 100t + 140
H(t) = 0 = </span><span>−16t^2 + 100t + 140
16t^2 - 100t -140 = 0
t = [100 +/- √ (100^2 -4(16)(-140) ) ] /(2(16))
t = 7.43 and t = - 1.18.
El que tiene sentido para la pregunta es t = 7.43 s.
Option B) 7 s (approximately)
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Answer:
a, (x-3/7)=2/3(3/2x-9/14), and c, 12.3x – 18 = 3(–6 + 4.1x).
Step-by-step explanation:
i just answered that question
Answer:
It's simple
Step-by-step explanation:
See what I did there? Simple?
Answer:
36 objects
Step-by-step explanation:
You want the value of x when t=9, so you're solving ...
9 = 0.007x^2 +0.003x
9 = 0.007(x^2 + 3/7x)
From here, we observe that an approximation is probably sufficient.
9/0.007 = x(x +3/7) . . . . . the expression on the right is nearly x^2
x ≈ 3/√.007 ≈ 35.9 ≈ 36
We can check:
.007(36)(36 3/7) = 9.18
.007(35)(35 3/7) = 8.68
To keep the computer busy for 9 seconds, it needs to sort 36 objects.
Answer:
This is true
Step-by-step explanation: