12/3=4
so m=4
6x4=24
6x1=6
24-6=18
Multiply like this. And it gives you your answer.
7.8•7.8•7.8
Hyp^2 = leg1^2 + leg2^2
hyp^2 -leg1^2 = leg2^2
17^2 - 8^2 = leg2^2
leg2^2 = 289 -64
leg2^2 = 225
leg2 = 15
Given:
Angled formed by ray BA and ray BC is 90 degrees.
To find:
The equation of line that bisects the angle formed by ray BA and ray BC.
Solution:
If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.
It is possible if the line passes though point B(-1,3) and other point (-2,4).
Equation of line is




Add 3 on both sides.


Therefore, the required equation of line is
.
Answer:
is this weird but in all my years of school I've never learn something like this