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3 years ago

Solve this system of equations algebraically:

Mathematics

1 answer:

Rom4ik [11]3 years ago

6 0

Answer:

the answer is 5,90

Step-by-step explanation:

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Select the polynomial that can be factored as (3x - 4)^2

Elodia [21]

Second binomial formula
(a - b)^2 = a^2 - 2ab + b^2
(3x - 4)^2 = (3x)^2 - 2 × 3x × (-4) + (-4)^2
=9x^2 + 24x - 16

6 0

3 years ago

Graph the line passing through the given point and having the given slope. Give the slope intercept form of the equation of the

shutvik [7]

Equation of the line is y=mx+b
the line passing through point (1;-2) so x=1 y=-2
m=-0.5 so put all these values in equetion and found value of b
-2=-0.5*1+b
-2=-0.5+b
b=-1.5
so equation of the line is y=-0.5x-1.5
Answer:
equation of the line is y=-0.5x-1.5

6 0

3 years ago

Read 2 more answers

Bao and Calvin use 6 lemons to make ever 4auarts of lemonade. They want to make 12 quarts of lemonade. How many lemons do they n

zalisa [80]

They are going to need 18 lemons

7 0

3 years ago

From a 28-inch by 28-inch piece of metal, squares are cut out of the four corners so that the sides can then be folded up to mak

elixir [45]

Answer:t The volume of the box as a function of x is given by

$Volume=(28-2x)^2x$

Step-by-step explanation:

Since we have given that

Length of metal = 28 inch

Width of metal = 28 inch

Since squares are cut out of the four corners so that the sides can then be folded up to make a box.

Let the length of the sides of the squares that are cut out be 'x'.

So, Length of box would be

$28-2x$

Width of the box would be

$28-2x$

Height of the box would be x.

As we know the formula for "Volume of box":

$Volume=(28-2x)(28-2x)x\\\\Volume=(28-2x)^2x$

Hence, the volume of the box as a function of x is given by

$Volume=(28-2x)^2x$

3 0

3 years ago

J=UC solve for c please

mart [117]

»»————-　★　————-««

I believe your answer is:

$c=\frac{j}{u}; u\neq 0$

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$\boxed{\text{Solving for 'c'...}}}\\\\j = uc \\------------\\\rightarrow \frac{j=uc}{u}\\\\\rightarrow \frac{j}{u}=c\\\\\rightarrow \boxed{c=\frac{j}{u}}}; u\neq 0$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

8 0

3 years ago