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expeople1 [14]
3 years ago
10

Solve this system of equations algebraically:

Mathematics
1 answer:
Rom4ik [11]3 years ago
6 0

Answer:

the answer is 5,90

Step-by-step explanation:

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Whelp plzz................................................
kondaur [170]

Answer:

7/9 and 6

Step-by-step explanation:

Coefficients are intergers that are parted with a variable.

7/9 and 6 are the coefficients

7 0
2 years ago
Solve each equation. Show your work<br><br> 13a=-5<br> 12−b=12.5<br> -0.1=-10c
amid [387]
1) 13a=-5
Make a the subject of the formula by dividing both sides by 13(the coefficient of a)
13a/13=-5/13
Therefore a= -0.385

The second one). 12-b= 12.5
You take the 12 to the other side making b subject of the formula (-b in this case)
-b= 12.5-12
-b= 0.5
(You cannot leave b with a negative sign so you will divide both sides by -1 to cancel out the negative sign)

-b/-1= 0.5/-1
Therefore b=-0.5

The third one). -0.1= -10c
You will divide both sides by the coefficient of c(number next to c) which is -10
-0.1/-10= -10c/-10

Hence, c= 0.01
5 0
3 years ago
The model represents an equation.
Llana [10]
It is 3 because if you count it 5-11 that’s 6 but you have to divide it by 2 sense there is 2 so that answer is 4
5 0
3 years ago
Read 2 more answers
A cross-country team had a total of 10 practices last week, with each practice being in the morning or the afternoon. During eac
GalinKa [24]

x= morning

y = afternoon

 x + y = 10

x=10-y

5x + 6y =57

5(10-y) +6y =57

50-5y +6y =57

y=7

x=10-7 =3

 check 3*5 = 15, 7*6 = 42, 42 + 15 = 57


3 morning practices

3 0
3 years ago
Question ok iterations help would be greatly appreciated!
Alexandra [31]

your answer would be A. I would hope this is right

6 0
3 years ago
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