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tensa zangetsu [6.8K]
3 years ago
10

Write the equation of the line that passes through the points (4,8) and (1, -8). Put

Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0

Answer:

3y - 16x = -40

Step-by-step explanation:

Given the coordinate points (4,8) and (1, -8).

The point slope form of the equaton is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is the point on the line

Get the slope

m = -8-8/1-4

m = -16/-3

m = 16/3

Get the required equation using the point (1, -8)

y - (-8) = 16/3 (x-1)

y+8 = 16/3 (x-1)

3(y+8) = 16(x-1)

3y + 24 = 16x - 16

3y - 16x = -16 - 24

3y - 16x = -40

Hence the required equation is 3y - 16x = -40

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Paul has 12 coins in his pocket, consisting entirely of dimes and quarters. If he has a total of 195 cents in coins, how many co
anyanavicka [17]

Let x be the number of dimes

and y be the number of quarters

Total number of coins = 12

So number of dimes + number of quarters = total number of coins

x + y = 12 ---------> equation 1

We know, 1 Quarter = 25 cents, 1 Dime = 10 cents, total cents = 196

y quarters = 25y cents , x dimes = 10x cents

x dimes + y quarters = 195 cents

10x + 25y = 195 -----------> equation 2

Now solve both equations

x + y =12, we solve for y by subtracting x on both sides

y = 12-x

Now substitute y in second equation

10x + 25(12-x) = 195

10x + 300 -25x = 195 (combine like terms)

-15x + 300 = 195 (subtract 300 on both sides)

-15x = -105 ( divide by -15)

x=7

y= 12-x

y=12-7 = 5

The number of dimes = 7

Number of quarters = 5






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