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tensa zangetsu [6.8K]
3 years ago
10

Write the equation of the line that passes through the points (4,8) and (1, -8). Put

Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0

Answer:

3y - 16x = -40

Step-by-step explanation:

Given the coordinate points (4,8) and (1, -8).

The point slope form of the equaton is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is the point on the line

Get the slope

m = -8-8/1-4

m = -16/-3

m = 16/3

Get the required equation using the point (1, -8)

y - (-8) = 16/3 (x-1)

y+8 = 16/3 (x-1)

3(y+8) = 16(x-1)

3y + 24 = 16x - 16

3y - 16x = -16 - 24

3y - 16x = -40

Hence the required equation is 3y - 16x = -40

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Step-by-step explanation:

By using mid point theorem we get,

VT=2BC

x+6=2(x+5)

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3 years ago
5/9 4.9 meters tall ratio
Keith_Richards [23]
5 + 9 = 14

4.9 / 14 = 0.35

0.35 * 5 = 1.75

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3 years ago
Which points lie on the line whose equation is 8x - 2y + 7 = -9? Select all that apply.
Anestetic [448]

Answer:

A.(-2, 0)

C. (-1.4)

Step-by-step explanation:

we know that

If a point lie on the line, then the point must satisfy the equation of the line (makes the equation true)

we have

8x-2y+7=-9

subtract 7 both sides

8x-2y=-9-7

8x-2y=-16

divide by 2 both sides

4x-y=-8

Substitute the value of x and the value of y of each point in the linear equation and analyze the result

<u><em>Verify each point</em></u>

case A) we have

(-2, 0)

For x=-2, y=0

substitute

4(-2)-(0)=-8

-8=-8 ---> is true

so

the point lie on the line

case B) we have

(1, 3)

For x=1, y=3

substitute

4(1)-(3)=-8

1=-8 ---> is not true

so

the point not lie on the line

case C) we have

(-1, 4)

For x=-1, y=4

substitute

4(-1)-(4)=-8

-8=-8 ---> is true

so

the point lie on the line

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(1, -4)

For x=1, y=-4

substitute

4(1)-(-4)=-8

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so

the point not lie on the line

case E) we have

(0, -1)

For x=0, y=-1

substitute

4(0)-(-1)=-8

1=-8 ---> is not true

so

the point not lie on the line

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3 years ago
If you are examining a function over an interval ( a , b ) , for a and b finite, is it possible not to have an absolute maximum
uysha [10]

Yes, it is not possible to have an absolute maximum or absolute minimum.

Here,

We are examining a function over an interval ( a , b ) , for a and b finite,

We have to find,  is it possible not to have an absolute maximum or absolute minimum.

What theorem indicates the existence of absolute maxima or absolute minima of a function?

If f is continuous on a closed interval [a, b] (that is: on a closed and bounded interval), then, the Extreme Value Theorem indicates the existence of an absolute maximum or minimum value of f on the interval [a, b].

Now,

The function is define over an interval (a, b).

Hence, the function is define on open interval.

So, it is not possible to have an absolute maximum or absolute minimum.

Learn more about the existence of maxima and minima visit:

brainly.com/question/6787214

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3 0
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F(x)=9x^2+6x+1 what is the x-intercepts
gayaneshka [121]
X-intercept is (-1/3 , 0)
8 0
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