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tensa zangetsu [6.8K]
3 years ago
10

Write the equation of the line that passes through the points (4,8) and (1, -8). Put

Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0

Answer:

3y - 16x = -40

Step-by-step explanation:

Given the coordinate points (4,8) and (1, -8).

The point slope form of the equaton is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is the point on the line

Get the slope

m = -8-8/1-4

m = -16/-3

m = 16/3

Get the required equation using the point (1, -8)

y - (-8) = 16/3 (x-1)

y+8 = 16/3 (x-1)

3(y+8) = 16(x-1)

3y + 24 = 16x - 16

3y - 16x = -16 - 24

3y - 16x = -40

Hence the required equation is 3y - 16x = -40

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