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RideAnS [48]
3 years ago
5

24,12,6,...find the 8th term.​

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0

Answer:

a = 24

r = 1/2

<h3>8th term = ar^(n-1)</h3><h3> = 24. (1/2)^-1/2</h3>
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4 1/5 meters long and 2/3 meter wide what is the answer? :( ≈(
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4 13/15

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4 1/5 + 2/3  

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Write an equation in general form for the line passing through (-12,-1) and perpendicular to the line whose equation is 6x-y-4=0
Rus_ich [418]

The Solution:

Given the equation of a line:

6x-y-4=0

We are required to find the equation of a line that is perpendicular to the given line and passes through the point (-12,-1).

Step 1:

Determine the slope of 6x-y-4=0.

\begin{gathered} \text{  Express y in terms of x.} \\ 6x-4=y \\ y=6x-4 \end{gathered}

The coefficient x, after making y the subject of the formula, is the slope of the given line. That is:

\begin{gathered} \text{ The slope of }6x-y-4=0\text{ is 6} \\  \\ Slope=m_1=6 \end{gathered}

Step 2:

Find the slope of the required line:

Since the two lines are perpendicular, the slope is:

\begin{gathered} m_2=\frac{-1}{m_1}=\frac{-1}{6} \\  \end{gathered}

Step 3:

Find the equation of the line that passes through point (-12,-1)

By formula,

y-y_1=m_2(x-x_1)

In this case,

\begin{gathered} x_1=-12 \\ y_1=-1 \end{gathered}

Substituting these values in the formula, we get the required equation is:

\begin{gathered} y--1=\frac{-1}{6}(x--12) \\  \\ y+1=-\frac{1}{6}(x+12) \end{gathered}

Cross multiplying, we get

\begin{gathered} 6y+6=-x-12 \\  \\ 6y+x+6+12=0 \\  \\ 6y+x+18=0 \end{gathered}

Therefore, the correct answer is:

6y+x+18=0

5 0
1 year ago
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