Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
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Answer:
the answer is 2
Step-by-step explanation:
Of means multiplication. So the question is 1/3 X 1 1/2. First make 1 1/2 improper: 3/2. Then multiply the numerators (top numbers) and denominaters (bottom numbers): 1x3=3, 3x2=6, =3/6. Now simplify 3/6=1/2. Then multiply that by 2, since he used 2 pieces: 1/2x2=1. John used 1 meter :)