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3 years ago

Somebody pwease answer my last question pleasee (fwee points)

Mathematics

2 answers:

sveticcg [70]3 years ago

8 0

Answer:

the other answer is on point

Goryan [66]3 years ago

3 0

Answer: Nothing. You didn’t bother adding an image regarding the question.

Step-by-step explanation:

Above.

You might be interested in

A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of $20. Opt

sdas [7]

Answer:

40$

Step-by-step explanation:

they have

20$

40hours

i=prt

multiplication of both

=40×20×5/100

=40$

the amount required at the week is 40$

7 0

3 years ago

Evaluate the expression if a = 2, b = −3, c = −4, h = 6, y = 4, and z = −1.

scZoUnD [109]

Step-by-step explanation:

Hope it helps. Please mark as brainliest.

6 0

3 years ago

Find the discriminant.

qwelly [4]

In order to find the discriminant:
b^2-4ac

A= 1, B= 6, C=8

(6)^2-4(1)(8) = 4

Therefore, the equation has one real solution

4 0

3 years ago

Polly measures the height of a bookcase to be 2 feet, 10 inches.

AVprozaik [17]

34 inches

Explanation:

There are 12 inches to 1 foot. So for 2 feet we have 2 lots of 12

So we have:

(2×12) inches +10 inches

24+10 inches

34 inches

4 0

3 years ago

The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source

Bezzdna [24]

Answer:

The voltage at the middle source is $(2-4\mathbf{i})\ V$

Step-by-step explanation:

Voltage Sources in Series

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

$2 + 6\mathbf{i}$

$a + b\mathbf{i}$

$2 - 5\mathbf{i}$

The sum of these voltages is:

$V_t=4+a+(6+b-5)\mathbf{i}$

Operating:

$V_t=4+a+(1+b)\mathbf{i}$

We know the total voltage is $6-3\mathbf{i}$ , thus:

$4+a+(1+b)\mathbf{i}=6-3\mathbf{i}$

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is $(2-4\mathbf{i})\ V$

5 0

3 years ago