We have the following equation:
h (t) = - 16t ^ 2 + 161t + 128
We substitute the value of h (t) = 170:
170 = -16t ^ 2 + 161t + 128
We rewrite the equation:
-16t ^ 2 + 161t + 128 - 170 = 0
-16t ^ 2 + 161t - 42 = 0
We look for the roots of the equation:
t1 = (161/32) + root (23233) / 32
t2 = (161/32) - root (23233) / 32
Answer:
The object is 170 feet off the ground at the following times:
t1 = (161/32) + root (23233) / 32
t2 = (161/32) - root (23233) / 32
Answer:
16/24
Step-by-step explanation:
9/12–> simplify to 3/4
3/4=15/20
24/32=3/4
6/8=3/4
16/24 is not equal
Answer:
√2/2
Step-by-step explanation:
If sinP = √2/2,
Rationalize;
√2/2
= √2/2,*√2/√2
√4/2√2
= 2/2√2
= 1/√2
Hence sinP = 1/√2
Take sin inverse of both sies
arcsinP = arcsin1/√2
P = 45 degrees
cos P = Cos 45
= 1/√2
= 1/√2 * √2/√2
= √2/2
Hence the value of cosP is √2/2
Answer: 1 + 1 = 2
Step-by-step explanation:because that's how we've defined it, in the same way that the word "cat" refers to small, furry, feline creatures because that's how we've defined it.
Answer:
C. 7 hours
Step-by-step explanation:
Let the time for the trip out be represented by t. Then the time for the return trip is t-1. The distance was the same for both trips, so we have ...
distance = speed × time
300t = 350(t -1)
300t = 350t -350 . . . . eliminate parentheses
350 = 50t . . . . . . . . . . add 350-300t
7 = t . . . . . . divide by 50
The trip out took 7 hours.
