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kirill [66]
2 years ago
6

X I ㅗ ] Factor: -2/3 out of -3X - 12

Mathematics
1 answer:
sesenic [268]2 years ago
3 0

Answer:what is this

Step-by-step explanation:

bruh

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In a particular region, 6% of the population is thought to have a certain disease. A standard diagnostic test has been found to
pochemuha

Answer:

The positive predictive value ≈ 30.012%

Step-by-step explanation:

(a) The given percentage of the people in the region that have the disease, P(D) = 6% = 0.06

The percentage people correctly identified as having the disease by the standard diagnostic test = 91%

The percentage of people incorrectly identified as having the disease by the standard diagnostic test, P(T + |H) = 8%

Therefore, the sensitivity of the test, P(T + |D) = 0.91

The specificity of the test, P(T - |H) = 1 - 0.08 = 0.92

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The number of non-diseased that test positive by the test is 0.08 × 1000 = 80 people which are false positives

Therefore, the number of diseased diagnosed as negative is 0.08 × 60 = 4.8

Therefore, we have;

\begin{array}{cccc}&Deseased&Non-diseased& Diseased + Non-diseased\\Test  \ +ve&60.06&80& 140.06\\Test \ -ve&4.8&855.4&\end{array}

The positive predictive value = Diseased +ve/(Diseased +ve + Non-diseased  +ve)

The \ positive \  predictive  \ value = \dfrac{Diseased +ve}{Diseased +ve + Non-diseased  +ve} \times 100

Therefore;

The positive predictive value = 60.06/(60.06 + 140.06) × 100 ≈ 30.012%

7 0
3 years ago
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