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icang [17]
3 years ago
11

8767453x20=175349060

Mathematics
1 answer:
kolbaska11 [484]3 years ago
3 0

Answer:

the calculation is correct but

what am I supposed to do with this

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I've done the y = equations but I don't know how to do this one.
Tems11 [23]

Consider the equation

-10x-y=-20

1) First row of the table

Set x=0 and solve as follows:

\begin{gathered} -10(0)-y=-20 \\ \Rightarrow-y=-20 \\ \Rightarrow y=20 \end{gathered}

The answer is y=20 and the pair x-y is (0,20)

2) Second row

Set x=1 and solve, as follows:

\begin{gathered} -10(1)-y=-20 \\ \Rightarrow-10-y=-20 \\ \Rightarrow-y=-10 \\ \Rightarrow y=10 \end{gathered}

The answers are y=10 and (1,10)

3) Third row.

Set y=0 and solve as follows:

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Current rules for telephone area codes allow the use of digits​ 2-9 for the first​ digit, and​ 0-9 for the second and third​ dig
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Using the fundamental counting theorem, we have that:

  • 648 different area codes are possible with this rule.
  • There are 6,480,000,000 possible 10-digit phone numbers.
  • The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

  • 8 options for the first digit.
  • 9 options for the second and third.

Thus:

8 \times 9 \times 9 = 648

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

  • 7 digits, each with 10 options.
  • 648 different area codes.

Then

648 \times 10^7 = 6,480,000,000


There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

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3 years ago
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She was charged 12 cents per kWh
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