Answer:
54 kg
Step-by-step explanation:
Total weight of 7 boys is 392 kg. And other 6 boys total weight is 338 kg.
So the 7th boy's weight is (392-338)=54 kg
54
338÷6=56.33
so it means that 7th boy is less than 56
338+54=392
392÷7=56
(4x^2y^3)^2 = 16x^4y^6
Answer
16x^4y^6
m∡2 = 90°
diagonals of a rhombus are perpendicular
the answer is D 8.8
part c
because i have done it before
