Ask question

Ask question

All categories

3 years ago

15

A store bought 300 toys at a cost of $24 each. The store sold all the toys at a percent markup of . Find the total selling pric

e.

1 answer:

BlackZzzverrR [31]3 years ago

3 0

Answer:

Step-by-step explanation:

You will have to write out the following:

25% of 24= ?

Then go ....turn 25 into a decimal

.25 x 24

24

x.25

——— ——) Which equals 6

Follow these steps on any one and as long as ur multiplication is right the answer will be right

You might be interested in

If there are 60 sides, what is the difference between the perimeter and π?

tangare [24]

You can sole it because I believe in you

5 0

3 years ago

Please help again thank you in advance

mojhsa [17]

Answer:

20 units

Step-by-step explanation:

Since the triangle is equilateral then all 3 sides are equal in length.

Equate any 2 sides and solve for x

4x = 3x + 5 ( subtract 3x from both sides )

x = 5

hence

4x = 4 × 5 = 20

3x + 5 = (3 × 5) + 5 = 15 + 5 = 20

7x - 15 = (7 × 5) - 15 = 35 - 15 = 20

The lengths of the sides are 20 units

7 0

3 years ago

Read 2 more answers

A highway traffic condition during a blizzard is hazardous. Suppose one traffic accident is expected to occur in each 60 miles o

o-na [289]

Answer:

a) 0.3408 = 34.08% probability that at least one accident will occur on a blizzard day on a 25 mile long stretch of highway.

b) 0.0879 = 8.79% probability that two out of these six blizzard days have no accident on a 25 mile long stretch of highway.

c) 0.4493 = 44.93% probability of no damaging accidents requiring a insurance claims on an 80 mile stretch of highway.

Step-by-step explanation:

We have the mean for a distance, which means that the Poisson distribution is used to solve this question. For item b, the binomial distribution is used, as for each blizzard day, the probability of an accident will be the same.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Suppose one traffic accident is expected to occur in each 60 miles of highway blizzard day.

This means that $\mu = \frac{n}{60}$ , in which 60 is the number of miles.

(a) What is the probability that at least one accident will occur on a blizzard day on a 25 mile long stretch of highway?

$n = 25$ , and thus, $\mu = \frac{25}{60} = 0.4167$

This probability is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.4167}*(0.4167)^{0}}{(0)!} = 0.6592$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.6592 = 0.3408$

0.3408 = 34.08% probability that at least one accident will occur on a blizzard day on a 25 mile long stretch of highway.

(b) Suppose there are six blizzard days this winter. What is the probability that two out of these six blizzard days have no accident on a 25 mile long stretch of highway?

Binomial distribution.

6 blizzard days means that $n = 6$

Each of these days, 0.6592 probability of no accident on this stretch, which means that $p = 0.6592$ .

This probability is P(X = 2). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{6,2}.(0.6592)^{2}.(0.3408)^{4} = 0.0879$

0.0879 = 8.79% probability that two out of these six blizzard days have no accident on a 25 mile long stretch of highway.

(c) If the probability of damage requiring an insurance claim per accident is 60%, what is the probability of no damaging accidents requiring a insurance claims on an 80 mile stretch of highway?

Probability of damage requiring insurance claim per accident is of 60%, which means that the mean is now:

$\mu = 0.6\frac{n}{60} = 0.01n$

80 miles:

This means that $n = 80$ . So

$\mu = 0.01(80) = 0.8$

The probability of no damaging accidents is P(X = 0). So

$P(X = 0) = \frac{e^{-0.8}*(0.8)^{0}}{(0)!} = 0.4493$

0.4493 = 44.93% probability of no damaging accidents requiring a insurance claims on an 80 mile stretch of highway.

6 0

3 years ago

What is the solution of the equation?<br> A. –5, 11<br> B. 5<br> C. 11<br> D. –11

rjkz [21]

Answer:

The solution is -5 or 11

Step-by-step explanation:

We are given the equation;

$4(3-x)^\frac{4}{3}-5=59$

We are supposed to solve the equation;

Taking 5 to the other side;

$4(3-x)^\frac{4}{3}=59+5$

$4(3-x)^\frac{4}{3}=64$

Dividing both sides by 4

$(3-x)^\frac{4}{3}=\frac{64}{4}$

$(3-x)^\frac{4}{3}=16$

We can cube both sides;

$((3-x)^\frac{4}{3})^3=16^3$

$(3-x)^4=4096$

Then we can get the fourth root on both sides of the equation;

$\sqrt[4]{ (3-x)^4} =\sqrt[4]{4096}$

We get;

$3-x=+8 or -8$

Solving for x

$3-x=8 and 3-x=-8$

Therefore;

$x=-5 or 11$

Therefore, the solution is -5 or 11

3 0

3 years ago

Think about all the ways in which a line and a parabola can intersect select all the numbers of ways in which a line in a parabo

creativ13 [48]

Answer:

0, 1, 2

Step-by-step explanation:

There is a way for them to intersect at 0 points, for example y=x^2 and y = -1

The way to intersect at 1 point is for the linear function to be tangent to the parabola, like y = x^2 and y = 0

The way to intersect 2 points is just for the linear function to be a secant to the parabola, like y = x^2 and y = 1

4 0

2 years ago

Read 2 more answers