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Sphinxa [80]
2 years ago
14

1 2/3 divided by 3/16

Mathematics
2 answers:
KATRIN_1 [288]2 years ago
4 0
1 2/3 divided by 3/16

5/3 / 3/16

KCF (Keep, Change, Flip)

5/3 * 16/3

5 * 16 = 80

3 * 3 = 9

5/3 * 16/3 = 80/9

8 8/9

Hope this helps!
stellarik [79]2 years ago
3 0

Answer:

80/9

Step-by-step explanation:

Step 1:  Convert 1 2/3 into the improper fraction 5/3.

Step 2:  Invert the divisor fraction, 3/16, and use the result (16/3) as a multiplier instead:  

5     16

----* ----- = 80/9

 3     3

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What is the surface area of the figure?<br> 240<br> 48<br> 192
Ulleksa [173]

Answer:

240 cm²

Step-by-step explanation:

We are required to determine the surface area of the figure;

To get the area we add the are of all the surfaces;

Area of triangle;

Area = 0.5 × b × h

There are two triangles;

Therefore;

Area of the two triangles;

Area = 0.5 × 6 × 8 × 2

        = 48 cm²

Area of the rectangles;

Area of a rectangle = Length × width

Area of the first rectangle;

 = 6 cm × 8 cm

 = 48 cm²

Area of the second rectangle

  = 8 cm × 8 cm

  = 64 cm²

Area of the third rectangle

 = 10 cm × 8 cm

 = 80 cm²

The total surface area will be;

 Area = 48 cm² + 48 cm² + 64 cm² + 80 cm²

          = 240 cm²

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Step-by-step explanation:

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The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. ​(
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Answer:

a) P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

b) z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}=  2.431

And if we use the z score we got:

P(z>2.431) =1-P(z

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

X \sim N(106,0.3)  

Where \mu=106 and \sigma=0.3

Part a

We are interested on this probability

P(X>106.11)

And we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

And using this formula we got:

P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score we got:

z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}=  2.431

And if we use the z score we got:

P(z>2.431) =1-P(z

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