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3 years ago

10

Find the slope of the line that passes through (4, 7) and (10, 6).

1 answer:

Bogdan [553]3 years ago

5 0

Answer:

i have written and above.

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A total of 35 pints of blood were collected at a local blood drive how many quarts of blood were collected

Step2247 [10]

There was a total of 17.5 quarts of blood that was collected.

Hope this helps! :-)

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3 years ago

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monitta

Answer:

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Step-by-step explanation:

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2 years ago

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HELPPPP!!! and get brainliest!!!!!!! + 22 points

ella [17]

Answer:

Step-by-step explanation:

b/c the function goes thur the point (1,4) we know it's 4 times more than f(x) so g(x) = 4 $x^{2}$

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3 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

3 years ago

the price of a gallon of unleaded gas was $2.86 yesterday. today, the price fell to $2.79. find the percent decrease. round answ

soldier1979 [14.2K]

So.. 2.86 - 2.79 is the amount in decrease or 0.07

so.. if we take 2.86 as the 100%, how much is 0.07 of that in percentage?

well $\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
2.86&100\\
0.07&x
\end{array}\implies \cfrac{2.86}{0.07}=\cfrac{100}{x}$

solve for "x"

3 0

3 years ago