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Tju [1.3M]
3 years ago
5

The bowl has a diameter of 10 inches. What is its radius?​

Mathematics
2 answers:
Zina [86]3 years ago
8 0

Answer:

5

Step-by-step explanation:

The radius is half of the diameter.

Licemer1 [7]3 years ago
7 0
5 because u divide it
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One leg of an isosceles right triangle measures 5 inches. Rounded to the nearest tenth, what is the approximate length of the hy
Komok [63]
Since it is isosceles right triangle, both legs = 5 inches.

using pythagoras theorem,


hypotenuse^2 = 5^2 +5^2 = 25+25 = 50
taking square root on both sides,
hypotenuse = sqrt 50  = 5 sqrt 2 or 7.071

rounded to nearest tenth,
length of hypotenuse is 7.1 inches.
5 0
3 years ago
Read 2 more answers
-2z=4z <br> Solve the equation
s344n2d4d5 [400]

-2z = 4z

0 = 6z

z = 0

Answer: z=0

8 0
3 years ago
the frame of a picture is 28 cm by 32 cm outside and is of uniform width.What is the width of the frame if 192 cm2 of the pictur
natita [175]

Answer:

The width of the frame is equal to 8\ cm  

Step-by-step explanation:

Let

x-------> the width of the frame picture

we know that

(28-2x)(32-2x)=192    

896-56x-64x+4x^{2} =192

4x^{2}-120x+704=0  

Simplify

x^{2}-30x+176=0

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}-30x+176=0

so

a=1\\b=-30\\c=176

substitute in the formula

x=\frac{30(+/-)\sqrt{(-30)^{2}-4(1)(176)}} {2(1)}

x=\frac{30(+/-)\sqrt{196}} {2}

x=\frac{30(+/-)14} {2}

x=\frac{30+14} {2}=22\ cm  ----> this solution is not logic

x=\frac{30-14} {2}=8\ cm  

The width of the frame is equal to 8\ cm  

8 0
3 years ago
Can Any of you help me with this please.
Hoochie [10]
The answer would be C
8 0
3 years ago
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A set of 9 numbers has a mean of 20. What additional number must be included in this set to create a new set with a mean that is
PIT_PIT [208]

<em>Greetings from Brasil...</em>

The average for a set of 9 elements will be

(A + B + C + D + E + F + G + H + I) ÷ 9 = 20

Let's make (A + B + C + D + E + F + G + H + I) like S

<em>(I chose S to remember a sum)</em>

Let us think.....

S ÷ 9 = 20

S = 20 × 9

S = 180

So,  (A + B + C + D + E + F + G + H + I) = 180

According to the statement, we will include a number (element J) in the sum to obtain a mean of (20 - 4), that is:

<h3>(A + B + C + D + E + F + G + H + I + J) ÷ 10 = (20 - 4)</h3>

as seen above, (A + B + C + D + E + F + G + H + I) = 180, then

(180 + J) ÷ 10 = 16

(180 + J) = 160

J = 160 - 180

<h2>J = - 20</h2><h2 />

So, including the number - 20 <em>(minus 20)</em> in the original mean we will obtain a new mean whose result will be 16

3 0
3 years ago
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