Answer: In the picture
please give me a brainliest answer
Answer:
a = 5.3
Step-by-step explanation:
Plug the length of the other two sides into the Pythagorean Theorem and solve.
a² + b² = c²
a² + 6² = 8²
a² + 36 = 64
a² = 28
a = √28
a = 5.291502622 ⇒ 5.3 (to the nearest tenth)
The length of "a" is 5.3.
Hope that helps.
Answer:
The correct option is;
Between 40 and 50 days
Step-by-step explanation:
The number of seeds that are produced by a plant maturing at age t, S(t), is given as follows;
S(t) = -0.3·t² + 30·t + 0.2
The proportion of plants maturing at age (t) in the plants to be engineered by the geneticist P(t) = 90000/(t + 100)
The number of seeds produced by the plants = S(t) × P(t) = (-0.3·t² + 30·t + 0.2)×(90000/(t + 100))
To find the maximum number of seeds, we differentiate using an online tool, and equate to zero to get;
d((-0.3·t² + 30·t + 0.2)×(90000/(t + 100)))/dt = (-27000·t² - 5400000·t + 269982000)/(t + 100)² = 0
(-27000·t² - 5400000·t + 269982000)/(t + 100)² = 27000(t - 41.419)(t + 241.419)/(t + 100)² = 0
t = 41.419 or t = -241.419
Therefore, in order to maximize the production of seed of the crops of the farmer, the geneticist should select between 40 and 50 days.
D^2 = (x2-x1)^2 + (y2-y1)^2
D =sqrt((10+5)^2 + (10-2)^2)
D P SQRT(15^2 + 8^2)
D = sqrt(225 +64)
D= sqrt(289)
D = 17
The distance is 17
There is one critical point at (2, 4), but this point happens to fall on one of the boundaries of the region. We'll get to that point in a moment.
Along the boundary 
, we have
which attains a maximum value of
Along 
, we have
which attains a maximum of
Along 
, we have
which attains a maximum of
So over the given region, the absolute maximum of 
is 1578 at (2, 44).
