To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Answer:
The second box plot best represents the data
Answer:
Z.
Step-by-step explanation:
I wrote down the subject with the number of students. I looked one by one to see if the number of students with the subject matched with the graph. Then I finally found that the last graph matched with what I written down.
Answer: Second option is correct.
Step-by-step explanation:
Since we have two spinners,
Each spinner has 10 equal sectors labeled with the numbers from 1 to 10.
Primes numbers from 1 to 10 is given by

So, number of outcomes shows a primes number from 1 to 10 = 4
Similarly ,
Composite numbers from 1 to 10 is given by

So, number of outcomes shows a composite number from 1 to 10 =5
∴ Total outcomes show a prime number on the first spinner and a composite number on the second spinner is given by

Thus, Second option is correct.