Using the relation between velocity, distance and time, it is found that the commute took 48 minutes.
<h3>What is the relation between velocity, distance and time?</h3>
Velocity is distance divided by time, that is:

For Lena, we have that d = 29, v = 36, hence the time in hours is given by:

In minutes, the time is given by:
tM = 0.8056 x 60 = 48.
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The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901
The amount of money gained after an investment is compounded is given by:

Where P is principal, A is the final amount, r is the rate, n is the number of times compounded per period and t is the time
Given that P = $1689, t = 4, r = 3% = 0.03, n = 1, hence:

The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901
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The true statement is h(2)=16.
<h3 /><h3>What is domain and range?</h3>
The domain of a function is the set of values that we are allowed to plug into our function. The range of a function is the set of values that the function assumes.
Given:
domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25,
Also, h(8) = 19 and h(-2) = 2,
Now,
2=h(-2)< h(2)<h(8) =19
h(8)=19≠21
h(13)> h(8) =19
h(-3)< h(-2) =2 [1 ≤ h(x) ≤ 25]
Hence, h(2)=16
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Answer:
y²/324 -x²/36 = 1
Step-by-step explanation:
Where (0, ±b) are the ends of the transverse axis and y = ±(b/a)x describes the asymptotes, the equation of the hyperbola can be written as ...
y²/b² -x²/a² = 1
<h3>Application</h3>
Here, we have transverse axis endpoints of (0, ±18) and asymptotes of y = ±3x, so we can conclude ...
b = 18
b/a = 3 ⇒ a = 18/3 = 6
The equation of the hyperbola in standard form is ...
y²/324 -x²/36 = 1
To simplify most teachers prefer to round to tenth or hundreth
best answers: 0.9, 0.87